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Delvig [45]
3 years ago
6

Select all of the answers that apply. which of the following cause volcanic eruptions?

Physics
2 answers:
Marina86 [1]3 years ago
7 0

The answers are A, B, and C.

Arada [10]3 years ago
4 0
I think it's A. Pressure and heat built up in the magma chamber.
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Describe an experiment to demonstrate the principles of the parallelogram of forces
Tcecarenko [31]

Answer:

There are 4 forces because a parallelogram has 4 sides.

It is a quadilateral. Let me know if I am right or not.

5 0
3 years ago
An information signal consists of a 25 Hz and a 75 Hz sine waves summed together. It is sampled at a frequency of 500 Hz, the hi
denpristay [2]

Answer:

Explanation:

An information contains

25Hz and 75Hz sine wave

Sample frequency is 500Hz

The analogy signal are generally

y(t) = Asin(2πx/λ - wt), w=2πf

y1(t)=Asin(2πx/λ - wt)

y1(t)=Asin(2πx/λ - 2π•25t)

y1(t)=Asin(2πx/λ - 50πt)

Similarly

y2(t)=Asin(2πx/λ - 150πt)

Using Nyquist theorem

Nyquist Theorem states that in order to adequately reproduce a signal it should be periodically sampled at a rate that is 2 times the highest frequency you wish to record.

From sampling

f(nyquist)=f(sample)/2

f(nyquist)=500/2

f(nyquist)=250Hz

From signal

The highest frequency is 150Hz

F(nyquist) = 2×F(highest)

f(nyquist)= 2×150

f(nyquist)= 300Hz

Sample per frequency Ns is given as

Ns=F(sample)/F(highest signal)

Ns=500/150

Ns=3.33sample/period

This is above nyquist rate of 2sample/period

So signal below 300Hz reproduced without aliasing.

The highest resulting frequency is 300Hz

6 0
3 years ago
Please can i have help with this question ​
kenny6666 [7]
Opposites attract so north goes to south and Vice versa. When the same poles are facing each other they push away when they are opposites they attract.
8 0
3 years ago
The cylindrical tub of a dryer in a laundromat rotates counterclockwise about a horizontal axis at 41.5 rev/min as it dries the
frozen [14]

Answer:

\theta = 49.81^0

Explanation:

Given that:

\omega = 41.5 \ rev/min\\\\\omega = 41.5 *\frac{1}{60}* 2 \pi\\\\\omega = 4.45 \ rad/s\\\\\\diameter = 0.748 m

If we let the piece of the close lose contact at ∠θ;

Then ; from force balance;

we have:

\\\\mg sin \theta = \frac{mv^2}{r}\\\\sin \theta = \frac{2v^2}{dg}\\\\\theta = sin^{-1} (\frac{2v^2}{dg})

where;

v = \frac{\omega d}{2}\\\\v =  \frac{4.45 *0.748}{2}\\\\v = 1.6643\\\\v^2 = 2.77

Again:

\theta = sin^{-1}(\frac{2v^2}{dg})\\\\\theta = sin^{-1}( \frac{2*2.77}{0.74*9.8})\\\\\theta = 49.81^0

6 0
3 years ago
Calculate the magnitude of the electric force between two charged balloons if one of the balloons has a charge of 15 * 10 ^ - 8
Sati [7]

Answer:

ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN ZAMN

Explanation:

3 0
2 years ago
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