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rjkz [21]
3 years ago
14

In an incompressible three-dimensional flow field, the velocity components are given by u = ax + byz; υ = cy + dxz. Determine th

e form of the z component of velocity. If the z component were not a function of x or y what would be the form be?
Physics
1 answer:
Ksivusya [100]3 years ago
8 0

An incompressible flow field F in a 3D cartesian grid with components u,v,w:

F = u + v + w

where u,v,w are functions of x,y,z

Must satisfy:

∇·F = du/dx + dv/dy + dw/dz = 0

We have a field F defined:

F = u+v+w, u = ax+byz, v = cy+dxz

du/dx = a, dv/dy = c

Recall ∇·F = 0:

∇·F = du/dx + dv/dy + dw/dz = 0

a + c + dw/dz = 0

dw/dz = -a-c

Solve for w by separation of variables:

w = ∫(-a-c)dz

w = -az - cz + f(x,y)

f(x,y) is some undetermined function of x and y

The question states that w is not a function of x and y, therefore f(x,y) = 0...

w = -az - cz

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Answer:

mass is in kg and velocity is in m/s for the answer to be in Joules

Explanation:

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3 years ago
NEED HELP!!! ANSWER THESE 5 QUESTIONS FOR 25 POINTS!!!! PLEASE ANSWER!! I WILL GIVE YOU BRAINEST
blagie [28]

Answer:

1. His heart rate is high and could indicate a problem.

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True

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5.Probably not since that system deals mostly with mobility.

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3 years ago
Radio wave radiation falls in the wavelength region of 10.0 to 1000 meters. What is the energy of radio wave radiation that has
dmitriy555 [2]

Answer:

Explanation:

Given

Wavelength of radiation \lambda =784\ m

We know Energy of wave with wavelength \lambda is given by

E=\frac{hc}{\lambda }

where h=Planck's constant

c=velocity of light

\lambda=wavelength of wave

E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{784}

E=2.53\times 10^{-28}\ J

Hence the energy of the wave with wavelength 784 m is 2.53\times 10^{-28}\ J

7 0
3 years ago
What is the intensity of a sound with a sound intensity level (SIL) 67 dB, in units of W/m^2?
vfiekz [6]

Answer:

The intensity of sound (I) = 3.16 x 10⁻⁶ W/m²

Explanation:

We have expression for sound intensity level (SIL),

              L=10log_{10}\left ( \frac{I}{I_0}\right )

Here we need to find the intensity of sound (I).

               L=10log_{10}\left ( \frac{I}{I_0}\right )\\\\log_{10}\left ( \frac{I}{I_0}\right )=0.1L\\\\\frac{I}{I_0}=10^{0.1L}\\\\I=I_010^{0.1L}

Substituting

          L = 67 dB and I₀ = 10⁻¹² W/m² in the equation

          I=I_010^{0.1L}=10^{-12}\times 10^{0.1\times 65}\\\\I_0=10^{-12}\times 10^{6.5}=10^{-5.5}=3.16\times 10^{-6}W/m^2

The intensity of sound (I) = 3.16 x 10⁻⁶ W/m²

8 0
3 years ago
PLS HELP How much power is used if an athlete lives a 100n Weight up 5m in 20 seconds
BlackZzzverrR [31]

Answer:

25J

Explanation:

power = work done ÷ time taken.

and work done = force applied × distance covered.

according to the question, the athlete lifts the weight of 100N upto 5m therefore;

100N × 5m = 500N/m

then onwards,

the work done (500 N/m) should be divided by the time taken to calculate the power,

500 ÷ 20s = 25J

is your answer.

hope this helped. :)

8 0
3 years ago
Read 2 more answers
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