Answer:
6.15.3 k
Explanation:
From the question we can see that
q = 0, Δu = w
Then,

putting values wet
=
T_f = 615.3 K
Answer:
it is option b
Explanation:
this is because neutralisation reaction takes place only between a base and an acid.
now, in OPTION A it is a neutral and base
OPTIONB it is acid and base
OPTION C both are base
OPTION D IT IS NOT POSSIBLE
Slow it down - I believe?
If the formula for density=m/v, you can manipulate this formula to the the mass. After manipulation, you get the equation for mass to be: m=density * volume. With density and volume given, we can find the mass.
mass= (8.9) * 6 = 53.4grams
Answer:
The energy released will be -94.56 kJ or -94.6 kJ.
Explanation:
The molar mass of methane is 16g/mol
The given reaction is:

the enthalpy of reaction is given as ΔH = -890.0 kJ
This means that when one mole of methane undergoes combustion it gives this much of energy.
Now as given that the amount of methane combusted = 1.70g
The energy released will be:
