Answer:
A. Can A will make a louder and stronger fizz than can B.
Explanation:
The solubility of a gas in a liquid decreases as the temperature increases, so the warmer can will have more undissolved carbon dioxide.
The warmer can will be under greater pressure, so it will make a louder and stronger fizz.
Answer:
a) Neutralisation
b) Combustion
c) Synthesis
d) Decomposition
e) Neutralisation
f) Double Displacement Reaction
h) Single Displacement Reaction
i) Double Displacement Reaction
j) Combustion
Explanation:
Synthesis is a reaction where various compounds/ elements react to form a totally new compound.
Decomposition is a reaction where a single compound breaks down into several components due to excessive heating or energy applied.
Single Displacement Reaction is a type of chemical reaction where an element reacts with a compound and takes the place of another element in that compound.
Double Displacement Reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.
Combustion is a reaction where a compound/ element oxidises in the presence of Oxygen.
Neutralisation reaction is a reaction where an acid reacts with a base to form a salt.
Answer:
Hey I dont know it but good luck!! :)
Explanation:
Answer:
The correct answer is 574.59 grams.
Explanation:
Based on the given information, the number of moles of NH₃ will be,
= 2.50 L × 0.800 mol/L
= 2 mol
The given pH of a buffer is 8.53
pH + pOH = 14.00
pOH = 14.00 - pH
pOH = 14.00 - 8.53
pOH = 5.47
The Kb of ammonia given is 1.8 * 10^-5. Now pKb = -logKb,
= -log (1.8 ×10⁻⁵)
= 5.00 - log 1.8
= 5.00 - 0.26
= 4.74
Based on Henderson equation:
pOH = pKb + log ([salt]/[base])
pOH = pKb + [NH₄⁺]/[NH₃]
5.47 = 4.74 + log ([NH₄⁺]/[NH₃])
log([NH₄⁺]/[NH₃]) = 5.47-4.74 = 0.73
[NH₄⁺]/[NH₃] = 10^0.73= 5.37
[NH₄⁺ = 5.37 × 2 mol = 10.74 mol
Now the mass of dry ammonium chloride required is,
mass of NH₄Cl = 10.74 mol × 53.5 g/mol
= 574.59 grams.
