Answer:
it's-D...........................
Answer:
The right solution according to the question is provided below.
Explanation:
According to the question,
(a)
The initial conditions will be:
DO = 
= 
= 
The initial oxygen defict will be:
Do = 
= 
The initial BOD will be:
Lo = 
= 
= 
(b)
The time reach minimum DO:
tc = ![\frac{1}{(kr-kd)} ln{(\frac{0.76}{0.61} )[1-\frac{1.674(0.76-0.61)}{0.61\times 6.453} ]}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%28kr-kd%29%7D%20ln%7B%28%5Cfrac%7B0.76%7D%7B0.61%7D%20%29%5B1-%5Cfrac%7B1.674%280.76-0.61%29%7D%7B0.61%5Ctimes%206.453%7D%20%5D%7D)
= 
By putting the values of log, we get
= 
The distance to reach minimum DO will be:
Xc = 
= 
= 
Answer C. is correct:
(molar mass of Mg) + (2 x molar mass of O) + (2 x molar mass of H)
:-) ;-)
IDensity is calculated by mass divided by volume. As you half the Hershey bar, mass and volume change by the same proportion. Therefore, density is the same.
The molar mass of CO2 is 44 grams per mole.
165 grams / 44 grams per mole of CO2 = 3.75 moles CO2
Using Avogadro’s law where 1 mole of substance equals
6.023 x 10^23 molecules
3.75 moles CO2 (6.023 x 10^23 molecules /mole) = 2.26 x 10^24 molecules CO2