<span>Using proportions,
if x is the unknown volume we have:
1.84 / 1 = 42.5 / x </span>
<span>
Multiply both sides above by x:
1.84*x / 1 = 42.5
1.84*x = 42.5
Divide both sides by 1.84:
x = 42.5 / 1.84</span>
<span>X = 23.10 mL</span>
Answer:
19 g
Explanation:
Data Given:
Sodium Chloride (table salt) = 50 g
Amount of sodium (Na) = ?
Solution:
Molecular weight calculation:
NaCl = 23 + 35.5
NaCl = 58.5 g/mol
Mass contributed by Sodium = 23 g
calculate the mole percent composition of sodium (Na) in sodium Chloride.
Since the percentage of compound is 100
So,
Percent composition of sodium (Na) = 23 / 58.5 x 100
Percent of sodium (Na) = 39.3 %
It means that for ever gram of sodium chloride there is 0.393 g of Na is present.
So,
for the 50 grams of table salt (NaCl) the mass of Na will be
mass of sodium (Na) = 0.393 x 50 g
mass of sodium (Na) = 19 g
Rf values may vary. Rf values vary depending on the material and solvent. The solvent that is used will alter the Rf value.
Rf values are typically higher for low polarity chemicals compared to higher polarity ones. Generally speaking, as polarity of a compound increases, so does its adsorptivity (i.e. the more polar the compound then the stronger it binds to the adsorbent). Solvents get more eluting as they become more polar.
The greater the compound's polarity, the more readily it will bind to the adsorbent, the closer it will come to the baseline, and the lower its Rf value. Many scientists use normal-phase flash chromatography with dichloromethane and methanol as the mobile phase to purify polar organic molecules. Due to methanol's high polarity and protic chemistry, it can frequently be difficult to optimize this solvent system.
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The answer is 20N as when the object is accelerating at 3 m/s2 it as a force of 10N applied to it so to get to 6m/s2 3(x2) = 6 so 10(x2) = 20
When there is heat released
