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vekshin1
3 years ago
7

A cold glass is left sitting outside on a hot day. Soon, water droplets form on the outside of the glass. Describe the events th

at must occur for the water droplets to form on the glass.
Physics
1 answer:
ikadub [295]3 years ago
8 0
Evaporation must happen
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You want to close an open door by throwing either a 400-g lump of clay or a 400-g rubber ball toward it. you can throw either ob
gogolik [260]
Refer to the diagram shown below.

Let m =  the mass (g) of the door.
Let v =  the launch velocity
Let u =  the velocity of the door after impact.

Elastic impact (rubber ball):
The rubber ball bounces off the door with presumably elastic impact, which means that both momentum and kinetic energy are conserved.
Conservation of momentum requires that
400v = -400v + mu
Therefore
u=( \frac{800}{m} )v

Inelastic impact (clay):
The clay sticks to the door after impact.
Conservation of momentum requires that
400g = (m+400)u
Therefore
u=( \frac{400}{m+400} )v

When we compare magnitudes of u for the door, we find that
u_{1}=( \frac{400}{m} )(2v), \,\, elastic \\\\ u_{2}=( \frac{400}{m+400} )v , \,\, inelastic
Clearly, the elastic impact creates a greater value of u for the door.

Answer:
The rubber ball creates a larger impulse to the door because the nature of its impact is approximately elastic.


5 0
3 years ago
Please help me!
sergeinik [125]

C. The Densities are equal.

<h3>What is density?</h3>

Density is mass per unit volume or mass of a unit volume of a material substance.

If m1, V1 and D1 = mass, volume  and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

According to the Question ,

V_{1} = 3V_{2}  , m_{2}  = \frac{1}{3} (m_{1} ) \\ \\= m_{1} = 3m_{2}

Therefore,

\frac{D_{1} }{D_{2} }  = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{3m_{2} }{3V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 1

Hence, D1 = D2

Learn more about density here:brainly.com/question/15164682

#SPJ1

6 0
3 years ago
How many different elements in this picture?<br> O 1<br> O2<br> 03<br> O4
Paraphin [41]

Answer: 3

Explanation:

4 0
3 years ago
The block in the diagram below is AT REST. However, the tension in the cable is not the only thing holding the block back. Stati
Vedmedyk [2.9K]

Answer:

The  tension in the rope is 229.37 N.

Explanation:

Given:

Mass of the block is, m=33.2\ kg

Coefficient of static friction is, \mu = 0.214

Angle of inclination is, \theta = 31.5°

Draw a free body diagram of the block.

From the free body diagram, consider the forces in the vertical direction perpendicular to inclined plane.

Forces acting are mg\cos \theta and normal N. Now, there is no motion in the direction perpendicular to the inclined plane. So,

N=mg\cos \theta\\N=(33.2)(9.8)\cos (31.5)\\N=277.415\ N

Consider the direction along the inclined plane.

The forces acting along the plane are mg\sin \theta and frictional force, f, down the plane and tension, T, up the plane.

Now, as the block is at rest, so net force along the plane is also zero.

T=mg\sin \theta+f\\T=mg\sin \theta +\mu N\\T= (33.2)(9.8)(\sin (31.5)+(0.214\times 277.415)\\T= 170+59.37\\T=229.37\ N

Therefore, the  tension in the rope is 229.37 N.

3 0
3 years ago
Explain Describe how a physical property,
nydimaria [60]

A change in the physical properties like mass or texture will not cause any change in the substance because the composition of the substance will retain the same.

<u>Explanation:</u>

A change of the physical properties will affect only the size, shape and structure of the compound, it won't be affecting the composition of the compound. Since any kind of change in the physical properties of the compound will only affect the outermost structure of the compound or the size of the compound.

It will not change the bond structure and neither it will break any bonds, thus the substance will be as it is. So, there will be no change in the substance on changing the physical properties like mass or texture, as the composition and bonding in the substance will retain the same.

3 0
3 years ago
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