Take note of the reaction formula which is PCl5=Cl2+PCl3.
The Keq = [Cl2] * [PCl3] / [PCl5]=2.24*10^-2.
For the reason that the volume is 1 liter, the concentration of Cl2 will be computed through: <span>(2.24 * 10^-2) * 0.235 / 0.174 </span> = 0.0303 mol/L is the answer.
Answer:
The total surface are of the bowl is given by: 0.0532*pi m² (approximately 0.166533 m²)
Explanation:
The total surface area of the semi-spherical bowl can be decomposed in three different sections: 1) an outer semi-sphere of radius 12 cm, 2) an inner semi-sphere of radius 10 cm, and 3) the edge, which is a 2-dimensional ring with internal radius of 10 cm and external radius of 12 cm. We will compute the areas independently and then sum them all.
a) Outer semi-sphere:
A1 = 2*pi*r² = 2*pi*(12 cm)² = 288*pi cm² = 904.78 cm²
b) Inner semi-sphere:
A2 = 2*pi*(10 cm)² = 200*pi cm² = 628.32 cm²
c) Edge (Ring):
A3 = pi*(r1² - r2²) = pi*((12 cm)²-(10 cm)²) = pi*(144-100) cm² = 44*pi cm² = 138.23 cm²
Therefore, the total surface area of the bowl is given by:
A = A1 + A2 + A3 = 288*pi cm² + 200*pi cm² + 44*pi cm² = 532*pi cm² (approximately 1665.33 cm²)
Changing units to m², as required in the problem, we get:
A = 532*pi cm² * (1 m² / 10, 000 cm²) = 0.0532*pi m² (approximately 0.166533 m²)
A skill set is explicitly taught or an activity is completed
Answer:
The phase difference between the reflected waves when they meet at the tuning fork is 159.29 rad.
Explanation:
Given that,
Frequency of sound wave = 240 Hz
Distance = 46.0 m
Distance of fork = 14 .0 m
We need to calculate the path difference
Using formula of path difference
Put the value into the formula
We need to calculate the wavelength
Using formula of wavelength
Put the value into the formula
We need to calculate the phase difference
Using formula of the phase difference
Put the value into the formula
Hence, The phase difference between the reflected waves when they meet at the tuning fork is 159.29 rad.
Answer:
THES IS NOT
Explanation:
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