Answer:
A capacitor has plates of area 8.25 * 10 ^ - 5 m ^ 2 . To create a capacitance of 3.35*10^ -10 F , how far apart should the plates be ?
Explanation:
I think with the increasing of temperatures of earths oceans and atmosphere is causing climate change and global warming. When the ocean heats up a lot of sea animals die and with the hot temps in the atmosphere is causing rare hot tempatures in some places in the world.
It can cause some intense storms but it mostly heats up the world and cause a lot of problems.
I hope i answered your question right.
Answer:
55.8W
Explanation:
P= V^2/R
R= V^2/P
For series connection
Req= R1+ R2= V^2/310 + V^2/180
R=V^2/P= V^2/310 + V^2/180
But V^2 will cancel out
P= 1/(1/310 + 1/180)
P= 55.8W
<span># of protons + # of neutrons = atomic mass</span>
Answer:
22 revolutions
Explanation:
2 rev/s = 2*(2π rad/rev) = 12.57 rad/s
The angular acceleration when it starting

The angular acceleration when it stopping:

The angular distance it covers when starting from rest:


The angular distance it covers when coming to complete stop:


So the total angular distance it covers within 22 s is 62.8 + 75.4 = 138.23 rad or 138.23 / (2π) = 22 revolutions