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2 years ago

Compare the different types of force?

Physics

1 answer:

olga nikolaevna [1]2 years ago

3 0

Answer:

Applied Force.

Gravitational Force.

Normal Force.

Frictional Force.

Air Resistance Force.

Tension Force.

Spring Force.

Explanation:

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¿Qué energía cinética posee una pelota de tenis de 65 g que se sirve a una velocidad de 200 km / h?

vekshin1

Therefore, the kinetic energy of an object is proportional to the square of its velocity (speed). In other words, If there is a twofold increase in speed, the kinetic energy will increase by a factor of four. If there is a threefold increase in speed, the kinetic energy will increase by a factor of nine.

4 0

3 years ago

Gravity can be described as (2 points)

ladessa [460]

Answer:

"the force of attraction between two objects"

Explanation:

According to Newton's Universal Law of Gravitation, gravity is a force of attraction acting between objects that possess mass. The fact that we only observe gravitational attraction (as opposed to repulsion) makes gravity unique among the known forces.

6 0

3 years ago

A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50

PSYCHO15rus [73]

Answer:

(a). The value of d is 0.056 cm and 1.496 cm.

(b). The time period is 1.35 sec.

Explanation:

Given that,

Length = 50.00 cm

Time period = 2.50 s

Time period of pendulum is defined as the time for one complete cycle.

The period depends on the length of the pendulum.

Using formula of time period

$T=2\pi\sqrt{\dfrac{I}{mgh}}$

Where, I = moment of inertia

We need to calculate the value of d

Using parallel theorem of moment of inertia

$I=I_{cm}+md^2$

For a meter stick mass m , the rotational inertia about it's center of mass

$I_{cm}-\dfrac{mL^2}{12}$

Where, L = 1 m

Put the value into the formula of time period

$T=2\pi\sqrt{\dfrac{\dfrac{mL^2}{12}+md^2}{mgd}}$

$T=2\pi\sqrt{\dfrac{L^2}{12gd}+\dfrac{d}{g}}$

$T^2=4\pi^2(\dfrac{L^2}{12gd}+\dfrac{d}{g})$

Multiplying both sides by d

tex]T^2d=4\pi^2(\dfrac{L^2}{12g}+\dfrac{d^2}{g})[/tex]

$(\dfrac{4\pi^2}{g})d^2-T^2d+\dfrac{\pi^2L^2}{3g}=0$

Put the value of T, L and g into the formula

$4.028d^2-6.25d+0.336=0$

$d = 0.056\ m, 1.496\ m$

The value of d is 0.056 cm and 1.496 cm.

(b). Given that,

L = 50-5 = 45 cm

We need to calculate the time period

Using formula of period

$T=2\pi\sqrt{\dfrac{l}{g}}$

Put the value into the formula

$T=2\pi\sqrt{\dfrac{45\times10^{-2}}{9.8}}$

$T=1.35\ sec$

Hence, (a). The value of d is 0.056 cm and 1.496 cm.

(b). The time period is 1.35 sec.

7 0

3 years ago

The velocity of blood flow is the lowest in capillaries because

Varvara68 [4.7K]

Answer:

the total cross-sectional area of the capillaries is greater than the total cross-sectional area of the arteries or any other part of the circulatory system.

Explanation:

Blood velocity is not the same in all areas. In the capillaries it is where there is less speed, while in arteries and veins it is quite similar. This is due to the cross-sectional area of each of the vessels. It is a mistake to think of a vein, artery or capillary individually. We have to put them all together to see that the total area of the capillaries is 100 times larger than that of the arteries or veins. Blood flowing through arteries or veins is going faster because there is less area.

Blood velocity is inversely proportional to each of the areas of its territories. The greater the area, the lower the speed.

6 0

3 years ago

Consider a neutron star of radius 10 km that spins with a period of 0.8 seconds. Imagine a person is standing at the equator of

Arada [10]

Answer:

a = 616850.28 m/s²

Explanation:

Given that,

The radius of the neutron star, r = 10 Km

= 10,000 m

The time period of the neutron star, T = 0.8 s

The centripetal acceleration is given by the formula,

a = v²/r

The linear velocity is given by the relation,

v = rω

The time taken to complete one complete rotation is given by the relation

T = 2π /ω

Where,

ω = 2π / T

Substituting v and ω into the equation for centripetal acceleration. It becomes

a = 4π²r/T²

Substituting the given values in the above equation

a = 4π² x 10000 / 0.8²

= 616850.28 m/s²

Hence, the centripetal acceleration of this person is, a = 616850.28 m/s²

8 0

3 years ago