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dedylja [7]
3 years ago
7

Calculate the mass percent of a solution that is prepared by adding 68.1 g of NaOH to 341 g of H20.

Chemistry
1 answer:
Sati [7]3 years ago
5 0

mass percent of the solution = 16.64%

Explanation:

We calculate the mass percent of a solution using the following formula:

mass percent = (mass of the solute / mass of the solution) × 100

mass of the solute = 68.1 g of NaOH

mass of the solution = mass of the solute + mass of water (H₂O)

mass of the solution = 68.1 + 341 = 409.1 g

mass percent = (68.1 / 409.1) × 100

mass percent = 16.64%

Learn more about:

mass percent

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It is a solution, because it's the alloy of tin and copper 
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Which rule for assigning oxidation numbers is correct?
AURORKA [14]

The incorrect rule for assigning oxidation numbers is Hydrogen is usually –1.

Hydrogen is usually +1

<h3>What is oxidation number?</h3>

Oxidation numbers can be defined as that number which is assigned to an element in chemical reaction which represents the number of electrons lost or gained.

So therefore, the incorrect rule for assigning oxidation numbers is Hydrogen is usually –1.

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7 0
2 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m
Bond [772]

Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
3 years ago
Why were colonists in new england angry at king james 2 abd governor edmund andros of new england?​
Pani-rosa [81]

His strict imposition of autocratic rule was supported by his appointment by the King, who otherwise was not directly involved.

Explanation:

Andros’ imposition of Episcopalian worship in the Old South Meeting house, Boston his vigorous enforcement of the Navigation Acts.

He had earned the enmity of the local populace by enforcing the restrictive Navigation Acts.

He had infuriated Puritans in Boston by promoting the Church of England, which was rejected by many Nonconformist New England colonists.

When news of the overthrow of James II (1688) reached Boston, the colonists revolted, deposing Andros and imprisoning him.

His requirement that landholders take out new land patents and his limitations upon town meetings and rights of local taxation all aroused sharp resentment in colonial America.

7 0
4 years ago
Why isn't the Liter a basic SI unit of measurement? (In your answer use at least one SI base unit of measurement and one other d
Y_Kistochka [10]

Answer:

What give me a few minutes I have to finish my test them I will answer in comments.

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3 years ago
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