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dedylja [7]
2 years ago
7

Calculate the mass percent of a solution that is prepared by adding 68.1 g of NaOH to 341 g of H20.

Chemistry
1 answer:
Sati [7]2 years ago
5 0

mass percent of the solution = 16.64%

Explanation:

We calculate the mass percent of a solution using the following formula:

mass percent = (mass of the solute / mass of the solution) × 100

mass of the solute = 68.1 g of NaOH

mass of the solution = mass of the solute + mass of water (H₂O)

mass of the solution = 68.1 + 341 = 409.1 g

mass percent = (68.1 / 409.1) × 100

mass percent = 16.64%

Learn more about:

mass percent

brainly.com/question/6992535

#learnwithBrainly

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One of the most likely products for the reaction would be Ag_2O

<h3>Chemical reactions</h3>

The reaction between AgNO_3 and NaOH yields 3 products which are Ag_2O (a precipitate), NaNO_3, and H_2O as shown by the equation below:

2 AgNO_3 + 2 NaOH --- > Ag_2O + 2 NaNO_3 + H_2O

One of the products precipitates out of the solution to give the reaction a precipitation reaction look.

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Which of the following is a change from a more condensed to a less condensed state of matter?
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The bond between sodium and chlorine in the compound sodium chloride (NaCl) is a/an:
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3 years ago
What is The pH and pOH of a 1.00x10-3M solution of CH3COOH (Ka=1.75x10-5) ?
zaharov [31]

Answer:

<h2>pH = 3.9</h2><h2>pOH = 10.1</h2>

Explanation:

Since CH _ 3COOH is a weak acid to find the pH of CH _ 3COOH we use the formula

pH =  -  \frac{1}{2}   log(Ka)  -  \frac{1}{2}  log(c)

where

Ka is the acid dissociation constant

c is the concentration

From the question

Ka of CH _ 3COOH = 1.75 × 10^-5

c = 1.00 × 10-³M

Substitute the values into the above formula and solve for the pH

That's

pH =  \frac{1}{2} ( -  log(1.75 \times {10 }^{ - 5} -  log(1.00 \times  {10}^{ - 3} )  )  \\   =  \frac{1}{2} (4.757  + 3) \\  =  \frac{1}{2}  \times 7.757) \\  = 3.8785 \:  \:  \:  \:  \:  \:  \:  \:

We have the answer as

<h3>pH = 3.9</h3>

To find the pOH we use the formula

pH + pOH = 14

pOH = 14 - pH

pOH = 14 - 3.9

We have the answer as

<h3>pOH = 10.1</h3>

Hope this helps you

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What is the molarity of a solution that has 2.52 grams of NaCO3 dissolved to
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Answer:

Explanation:

2.52g/ 0.125L= 20.16M

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