Question

The term "specific gravity" refers to the how much greater the solution density is than the density of water, e.g. if the specific gravity is 1.02, the solution density is 1.02 times the density of water A collapsible plastic bag contains a glucose solution. If it were out of the water, resting on a table, how mach would it weigh? Use 10 m/s for gravity and 1000 kg/m3 for the density of water. solution 1. 100N 2. 1.0 N If the average gauge pressure in the vein is 13600 Pa, what must be the minimum height of the bag in order to infuse glucose into the vein? Assume that the specific gravity of the solution is 1.03. The acceleration of gravity is 9.8 m/s .
a. 10000 N.
b. 5. 10 N.
c. 6. 1000 N.
d. 012 10.0N.

Answer 1

Answer:

Part a)

W = 10 N

Part b)

h = 1.35 m

Explanation:

Part a)

If object volume is 1 Ltr

density of the object is given as

$\rho = 10^3 \times 1.02$

$\rho = 1020 kg/m^3$

now weight of the object is given when it is placed on the table

$W = \rho V g$

$W = (1020)(10^{-3})(9.81)$

$W = 10 N$

Part b)

When pressure due to solution of the mixture is equal to the pressure inside the veins then only it will infuse into the veins

So here we will have

$\rho g h = P_{in}$

$\rho = 1.03 \times 10^3 kg/m^3$

$P_o = 13600$

now we have

$1.03 \times 10^3 (9.81) h = 13600$

$h = \frac{13600}{1.03 \times 10^3 \times 9.81}$

$h = 1.35 m$