8.97 g/cm^
D=m/v
D=43.5/4.85cm^3
D=8.97 g/cm^3
Sn + 2Cl2 ------> SnCl4
from reaction 2 mol 1 mol
from the problem 2.85 mol x mol
x=2.85*1/2≈1.43 mol SnCl4
Explanation:
"<em>Its bonds are formed by large differences in electronegativity" is the statement among the choices given in the question that is generally true about CaCl2.</em>
Answer:
Volume of AgNO₃ = 4.9 ml (Approx)
Explanation:
Given:
Total solution = 75 ml
Volume of AgNO₃ = 6.5%
Find:
Volume of AgNO₃
Computation:
Volume of AgNO₃ = Total solution x Volume of AgNO₃
Volume of AgNO₃ = 75 x 6.5%
Volume of AgNO₃ = 4.875
Volume of AgNO₃ = 4.9 ml (Approx)
Answer:
26.0 moles
Explanation:
Given the formula;
PV =nRT
P= pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = gas constant
T = temperature
n = PV/RT
n = 125 * 5/0.082 * (20 + 273)
n = 625/24.026
n = 26.0 moles
