The answer for the following problem is described below.
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Explanation:
Given:
enthalpy of combustion of glucose(Δ
of 
) =-1275.0
enthalpy of combustion of oxygen(Δ of 
) = zero
enthalpy of combustion of carbon dioxide(Δ of 
) = -393.5
enthalpy of combustion of water(Δ of 
) = -285.8
To solve :
standard enthalpy of combustion
We know;
Δ = ∈Δ (products) - ∈Δ (reactants)
(s) +6 (g) → 6 (g)+ 6 (l)
Δ = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]
Δ = [6 (-393.5) + 6(-285.8)] - [0 - 1275]
Δ = 6 (-393.5) + 6(-285.8) - 0 + 1275
Δ = -2361 - 1714 - 0 + 1275
Δ =-2800 kJ
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Hi , the answer is D because the moon is blocking the sun s rays .
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Answer:
ok :)
Explanation: genetically modified organisms (GMOs) are being made by inserting a gene from an external source such as viruses, bacteria, animals or plants (etc) into foods. Genetically modified foods seem to be not as healthy as unmodified foods, according to research. also many people are against it due to the fact that some people go overboard and add too many genetically modified organisms, which causes health risks and unfortunately harms people. sometimes genetically modified food contains toxins and antibiotics. srry i couldnt find much on the process but this is based off my background knowledge so yeah
