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emmainna [20.7K]
4 years ago
5

C. How many grams of Na2SiO3 can react with 0.800 g of HF?

Chemistry
1 answer:
finlep [7]4 years ago
5 0

Answer:

Mass = 0.610 g

Explanation:

Given data:

Mass of Na₂SiO₃ = ?

Mass of HF = 0.800 g

Solution:

Chemical equation:

Na₂SiO₃ + 8HF   →    H₂SiF₆ + 2NaF + 3H₂O

Number of moles of HF:

Number of moles = mass/ molar mass

Number of moles = 0.800 g/ 20 g/mol

Number of moles = 0.04 mol

Now we will compare the moles of HF and Na₂SiO₃.

           HF        :        Na₂SiO₃

            8          :          1

            0.04    :       1//8×0.04 = 0.005

Mass of Na₂SiO₃:

Mass = number of moles × molar mass

Mass =   0.005 mol  × 122.07 g/mol  

Mass = 0.610 g

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<u>Answer:</u>

<u>For a:</u> The chemical equation for the dissolution of sodium carbonate is Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)

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<u>Explanation:</u>

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Dissolution reaction is defined as the reaction in which a solid compound gets dissolved in water to form aqueous solution.

The chemical equation for the dissolution of sodium carbonate follows:

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The chemical equation for the ionization of sodium carbonate follows:

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  • <u>For b:</u>

Now, the anion formed which is CO_3^{2-} reacts with water to form conjugate acid.

The chemical equation for the reaction of anion with water follows:

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Hence, the net acid-base reaction of the anion formed and water is written above.

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