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madam [21]
3 years ago
14

Put the steps of the carbon cycle in order using Step 1 as your starting point. Step 1: Bacteria, through nitrogen fixation and

nitrification, convert nitrogen into a usable form.
Chemistry
1 answer:
Amanda [17]3 years ago
5 0

Answer:

The answer is explained below

Explanation:

Put the steps of the carbon cycle in order using Step 1 as your starting point

Step 1: Bacteria, through nitrogen fixation and nitrification, convert nitrogen into a usable form. The animal dies and decomposes, returning nitrogen back to the soil. Once nitrogen is in usable form, it is taken up by plants and assimilated into proteins.. An animal eats a plant and the nitrogen becomes part of the animal’s proteins.

The steps taking in the carbon circle using step 1 as the starting point is as follows:

Step 1:  Bacteria, through nitrogen fixation and nitrification, convert nitrogen into a usable form.

Bacteria convert nitrogen into nitrites and nitrates through the process of nitrification. Nitrites and nitrates are in the form that can be used by the plants

Step 2: Once nitrogen is in usable form, it is taken up by plants and assimilated into proteins.

The Nitrogen can only be used by the plants when in nitrites and nitrates form. When in this form, it is then assimilated into plant tissue as protein.

Step 3: An animal eats a plant and the nitrogen becomes part of the animal’s proteins.

An animal such as rabbit eats the plant and the protein in the plant becomes protein in the animal.

Step 4: The animal dies and decomposes, returning nitrogen back to the soil.

When the animal dies, the animal undergoes decomposition and the nitrogen in the animal is returned to the soil

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Determine the specific heat ofmaterial if a 12g sample absorbed 48j as it was heated from 20-40
devlian [24]

Answer:

c =0.2 J/g.°C

Explanation:

Given data:

Specific heat of material = ?

Mass of sample = 12 g

Heat absorbed = 48 J

Initial temperature = 20°C

Final temperature = 40°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  40°C -20°C

ΔT =  20°C

48 J = 12 g×c×20°C

48 J =240 g.°C×c

c = 48 J/240 g.°C

c =0.2 J/g.°C

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