The moles that are present in 150 g of ammonium hydrogen phosphite is 1.136 moles
<u><em>calculation</em></u>
<em>The formula of ammonium hydrogen phosphite = (NH4)2HPO4</em>
moles = mass/molar mass
mass= 150 g
molar mass of (NH4)2HPO4 = [ ( 14+ 1x4)2) +1 + 31 + ( 4 x16)] =132 g/mol
moles is therefore = 150 g/ 132 g/mol =1.136 moles
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Given :
Number of He atoms,
atoms.
To Find :
How many grams are their in given number of He atoms.
Solution :
We know, molecular mass of He is 4 g. It means that their are
atoms in 4 g of He.
Let, number of gram He in
atoms is x , so :

Therefore, grams of He atoms is 22.58 g .
Answer:
I'd Go. B. weigh everything, let the reaction happen, then weigh everything again.
The balanced equation for the ionization of the weak base pyridine,C5H5N in water, H2O
C_5H_5N ( aq.) + H2O ( l) ---------> C5H5NH+ (aq.) + OH- (aq.)
<h3>What is the balanced equation for the ionization?</h3>
Generally, Pyridine is characterized by a ring structure, in this characteristic ring structure N is sp2 hybridized, hence creating a lone pair present on N so s - character is more, as well as lone pair, is present.
Therefore, Considering The following functions of the equation:weak base pyridine,C5H5N in water, H2O
We write the balanced equation for the ionization as
C_5H_5N ( aq.) + H2O ( l) ---------> C5H5NH+ (aq.) + OH- (aq.)
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