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3 years ago

If you answer and explain I will give 25 points!

Chemistry

1 answer:

snow_tiger [21]3 years ago

7 0

Answer:535.5g

Explanation:

1) find the volume of the object

=L*W*H

=1.8*3.5*10.0

=63cm^3

2) the original formula is solving for the dencity which we have so...

D=M/V

M=D*V

M=8.5(63)

M=535.5g

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A chemical change occurs whenever

Talja [164]

Answer:

Explanation:

A chemical change happens when one chemical substance is transformed into one or more different substances, such as when iron becomes rust.

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3 years ago

DUE TOMORROW GIVING BRAINLIEST!

Elina [12.6K]

Answer:

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3 years ago

Read 2 more answers

Calculate the [H+] and pH of a 0.0040 M hydrazoic acid solution. Keep in mind that the Ka of hydrazoic acid is 2.20×10−5. Use th

Vera_Pavlovna [14]

Answer:

$[H^+]=0.000285$

$pH=3.55$

Explanation:

In this, we can with the ionization equation for the hydrazoic acid ( $HN_3$ ). So:

$HN_3~~H^+~+~N_3^-$

Now, due to the Ka constant value, we have to use the whole equilibrium because this is not a strong acid. So, we have to write the Ka expression:

$Ka=\frac{[H^+][N_3^-]}{[HN_3]}$

For each mol of $H^+$ produced we will have 1 mol of $N_3^-$ . So, we can use "X" for the unknown values and replace in the Ka equation:

$Ka=\frac{X*X}{[HN_3]}$

Additionally, we have to keep in mind that $HN_3$ is a reagent, this means that we will be consumed. We dont know how much acid would be consumed but we can express a subtraction from the initial value, so:

$Ka=\frac{X*X}{0.004-X}$

Finally, we can put the ka value and solve for "X":

$2.2X10^-^5=\frac{X*X}{0.004-X}$

$2.2X10^-^5=\frac{X^2}{0.004-X}$

$X= 0.000285$

So, we have a concentration of 0.000285 for $H^+$ . With this in mind, we can calculate the pH value:

$pH=-Log[H^+]=-Log[0.000285]=3.55$

I hope it helps!

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3 years ago

Rank the following acids in order of increasing acid strength. Key: Weakening of hydrogen bond and stability of resulting anion.

raketka [301]

Explanation:

The given compounds are oxyacids and in these compounds more is the electronegativity of the central atom more will be its acidic strength.

This is because more is the electronegativity of the central atom more will be the polarity of OH bond. As a result, the compound can readily lose $H^{+}$ ion.

Also, more is the electronegativity of central atom more will be the stability of conjugate base formed.

Thus, we can conclude that given compounds are arranged in increasing acid strength as follows.

HOI < $HOBr_{2}$ < $HOCl_{3}$ < HOF

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3 years ago

Suppose you are performing an extraction procedure with a carboxylic acid, like a benzoic or toluic acid Which layer should cont

wolverine [178]

Answer:

The correct answer is option A, that is, the organic layer.

Explanation:

One knows that non-polar solvent dissolves non-polar substances and the polar solvent dissolves polar substances, that is, like dissolved like. The toluic acid or benzoic acid refers to the carboxylic acids, which are non-polar or are very less polar in characteristics.

Therefore, they possess the tendency to remain in the organic solvent, which is non-polar like diethyl ether. The toluic acid's or benzoic acid's non-polar characteristic is because of the existence of huge hydrophobic rings of benzene. Hence, the correct answer is option A, that is, the organic layer.

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4 years ago