Question

Air is compressed in a cylinder such that the volume changes from 100.0 to 10.0 in^3. The initial pressure is 50.0 psia and the temperature is held at a constant 100.0 °F. How much work is required to change the volume? (Hint you will need to identify what psia means)

Answer 1

Answer:

5953.42 J

Explanation:

Given:

Initial volume, $V_i$= 100 in³

Final Volume, $V_f$ = 10 in³

Initial pressure = 50 psia

Temperature = 100° F = 310.93 K

For isothermal reversible process, work done is given as:

Work done = $-2.303RTlog_{10}\frac{V_f}{V_i}$

Where,

R is the ideal gas constant = 8.314 J/mol.K

or

Work done = $-2.303\times8.314\times310.93log_{10}\frac{10}{100}$

or

Work done = 5953.42 J