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GenaCL600 [577]
4 years ago
8

The large intestine ends in the ___.

Physics
2 answers:
pishuonlain [190]4 years ago
8 0
It ends at the Rectum
Anton [14]4 years ago
7 0

Answer:

THat BUtt hoLE

Explanation:

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Please help me out , im totally stuck on this!?
sladkih [1.3K]
According to first parity rule in a double stranded DNA %A=%T and %G=%C
<span> which means Adenine-Thymine and Guanine-Cytosine these pairs are present in equal amounts
</span>
8 0
3 years ago
A 1.0-m-tall vertical tube is filled with 20°C water. A tuning fork vibrating at 580 Hz is held just over the top of the tube as
Mademuasel [1]

Answer:

water heights of the tube are 0.851 m  , 0.553 m, 0.255 m

Explanation:

given data

frequency = 580 Hz

temperature = 20°C

tube = 1 m

to find out

water heights of the tube

solution

we will apply here formula for length that is

length L = v ( 2n -1 ) / 4f

here v is velocity o sound that is 343.2 m/s

so for n = 1

L = 343.2 ( 2(1) -1 ) / 4(580) = 0.147931 m

for n = 2

L = 343.2 ( 2(2) -1 ) / 4(580) = 0.443793 m

for n = 3

L = 343.2 ( 2(3) -1 ) / 4(580) = 0.739655 m

for n = 4

L = 343.2 ( 2(4) -1 ) / 4(580) = 1.035517 m is greater than 1

and so here  height is measured less than 1 m

so water heights of the tube are 1 m - 0.147931 m  , 1 m - 0.443793 m, 1 m - 0.739655 m

so water heights of the tube are 0.851 m  , 0.553 m, 0.255 m

3 0
3 years ago
What velocity must a 1210 kg car have in order to have the same momentum as the pickup truck in the sample problem
harina [27]

Answer:

P=mv 2250*25=56250

Explanation:

p of truck =2250*25 =56250

since p of truck = p of car

then p of car = 56250

therefore p of car = 1210 * v

or, 56520=1210v

or,v= 56520/1210=46.48

so, v of car is 46.48m/s

3 0
3 years ago
What is the velocity (in m/s) of a 550 kg roller coaster cart at the bottom of the track if it started with 990,000 J of gravita
sesenic [268]

Answer:

60m/s

Explanation:

initial energy = final energy

g.p.e = k.e

k.e = 0.5 × mass × velocity²

g.p.e = 990000J as per Question

990000Nm = 0.5 × 550 × V²

V² = 3600

V = 60m/s

4 0
3 years ago
Different between pulling and pushing force​
yuradex [85]

Answer:

Push and pull are both forces, but the difference is in their direction at which it is applied. If the force applied in the direction of motion of the particle then we call it push. If that force applied in the direction OPPOSITE to the motion of the particle then it it termed as pull

4 0
3 years ago
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