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emmasim [6.3K]
3 years ago
15

Simple physics (Final) (Pic provided)

Physics
1 answer:
Igoryamba3 years ago
3 0

Answer:

15m/s

Explanation:

Divide distance by time

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A 2.0-ohm resistor is connected in a series with a 20.0 -V battery and a three-branch parallel network with branches whose resis
Llana [10]

Answer:

Explanation:

Resolving the parallel resistor branches

\frac{1}{Rtotal} =\frac{1}{8.0ohm} +\frac{1}{8.0ohm} +\frac{1}{8.0ohm} =2.67Ohm

The equivalent resistor is now in series with the 2.0 Ohm resistor

so, by using Ohm's Law

I=\frac{V}{Rtotal+R} \\I=\frac{20.0V}{2.67Ohm+2.0Ohm} \\\\I= 4.28A

4 0
3 years ago
A proton is ejected from the sun at a speed of 2 x 10^6 m/s. How long does it take for this proton to reach earth? Answer in hou
wolverine [178]
The distance from the Sun to the Earth is 149,600,000 km.

d=149 600 000 \ km = 149 600 000 000 \ m = 1496 \cdot 10^8 \ m \\
v=2 \cdot 10^6 \ \frac{m}{s} \\ \\ \\
t=\frac{d}{v} \\ \\
t=\frac{1496 \cdot 10^8 \ m}{2 \cdot 10^6 \ \frac{m}{s}}=748 \cdot 10^2 \ s =\frac{748 \cdot 10^2 }{36 \cdot 10^2} \ h \approx \underline{\underline{20,78 \ h}}
5 0
3 years ago
What happens when the density of a medium increases
Anvisha [2.4K]
We all know that the sound travels faster through solids and then liquids and then through gases.
As far as i know solids are the medium through which the sound travels fast.

But in some websites I saw that as the density increases , the velocity of the sound decreases.If this statement is correct , how come the sound travels fastest through solids (since they have higher density) 

From this it is clear that not only sound as compression wave But also in the form of Shear wave travels in Solids

This makes it easier for sound to travel with higher speed in solids
8 0
3 years ago
Read 2 more answers
Holding onto a tow rope moving parallel to a frictionless ski slope, a 61.8 kg skier is pulled up the slope, which is at an angl
nata0808 [166]

Answer:

a) Frope= 71.7 N

b) Frope=6.7 N

Explanation:

In the figure the skier is simulated as an object, "a box".

a) At constant velocity we can say that the object is in equilibrium, so we apply the Newton's first law:

∑F=0

Frope=w*sen6.8°

Frope=71.71N

Take into account that w is the weight that is calculated as mass per gravitiy constant:

w=m*g

w=61.8Kg*9.8\frac{m}{s^{2} }

w=605.64N

b) In this case the system has an acceleration of 0.109m/s2.  Then, we apply Newton's second law of motion:

F=m*a

F=61.8Kg*0.109m/s2

Frope=6.73N

8 0
3 years ago
How much voltage (in terms of the power source voltage bV) will the capacitor have when it has started at zero volts potential d
Archy [21]

Answer:

The voltage is   V =   0.993V_b

Explanation:

From the question we are told that

   The time that has passed is  t = \frac{\tau}{2}

 Here \tau is know as the time constant

    The voltage of the  power source is   V_b

Generally the voltage equation for charging a capacitor is mathematically represented as

       V =  V_b  [1 - e^{- \frac{t}{\tau} }]

=>   V =  V_b  [1 - e^{- \frac{\frac{\tau}{2}}{\tau} }]

=>   V =  V_b  [1 - e^{- \frac{\tau}{2\tau} }]

=>   V =  V_b  [1 - e^{- \frac{1}{2} }]

=>   V =   0.993V_b    

5 0
2 years ago
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