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raketka [301]
3 years ago
12

Which of the following involves an endothermic reaction?

Physics
2 answers:
pav-90 [236]3 years ago
8 0
The answer would be c
photoshop1234 [79]3 years ago
7 0
It’s c :) A chemical hand warmer
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A car has a momentum of 20,000 kg • m/s. What would the car’s momentum be if its velocity doubles?
AnnyKZ [126]

To answer this question, it helps enormously if you know
the formula for momentum:

           Momentum = (mass) x (speed) .

Looking at the formula, you can see that momentum is directly
proportional to speed.  So if speed doubles, so does momentum.

If the car's momentum is 20,000 kg-m/s now, then after its speed
doubles, its momentum has also doubled, to 40,000 kg-m/s.

6 0
2 years ago
Read 2 more answers
Two charges of +4x10-SC and -4x10-5C are placed 1 meter apart. Using Coulomb's law, the force between them is 14.4 N.
Snowcat [4.5K]

Answer:

d. the force is reduced by one quarter to 3.6 n

Explanation:

6 0
2 years ago
3. According to Hund's rule, what's the expected magnetic behavior of vanadium (V)?
ivanzaharov [21]

Answer:

Diamagnetic

Explanation:

Hunds rule states that electrons occupy each orbital singly first before pairing takes place in degenerate orbitals. This implies that the most stable arrangement of electrons in an orbital is one in which there is the greatest number of parallel spins(unpaired electrons).

For vanadium V ion, there are 18 electrons which will be arranged as follows;

1s2 2s2 2p6 3s2 3p6.

All the electrons present are spin paired hence the ion is expected to be diamagnetic.

6 0
3 years ago
A car is moving at 19 m/s along a curve on a horizontal plane with radius of curvature 49m.
JulsSmile [24]

Answer:

\mu =0.75

Explanation:

<u>Frictional Force </u>

When the car is moving along the curve, it receives a force that tries to take it from the road. It's called centripetal force and the formula to compute it is:

F_c=m.a_c

The centripetal acceleration a_c is computed as

\displaystyle a_c=\frac{v^2}{r}

Where v is the tangent speed of the car and r is the radius of curvature. Replacing the formula into the first one

F_c=m.\frac{v^2}{r}

For the car to keep on the track, the friction must have the exact same value of the centripetal force and balance the forces. The friction force is computed as

F_r=\mu N

The normal force N is equal to the weight of the car, thus

F_r=\mu .m.g

Equating both forces

\displaystyle \mu .m.g=m.\frac{v^2}{r}

Simplifying

\displaystyle \mu =\frac{v^2}{rg}

Substituting the values

\displaystyle \mu =\frac{19^2}{(49)(9.8)}

\boxed{\mu =0.75}

7 0
3 years ago
Which of the following statements about the nuclear strong force is true?
lisabon 2012 [21]

Answer: 2, the nuclear strong force drops to practically nothing at large distances.

Explanation: The protons and neutrons in the nucleus share subatomic particles called pions. This exchange is what keeps the protons and neutrons stuck together in the nucleus. Despite the strong force being the strongest force, it has a very small range. This is because pions have very short lifespans. So, the strong force would have literally no effect at large distances.

Hope that helped! :)

4 0
3 years ago
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