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dedylja [7]
3 years ago
13

Why is a quantitative observation more useful than a non- quantitative one? Which of the following are quantitative?

Chemistry
1 answer:
daser333 [38]3 years ago
7 0
A quantitative observation is not necessarily more useful than a non-quantitative one. However, quantitative observations do allow one to find trends.

(a), the sun rising is a non-quantitative observation.

(b), knowledge of the numerical relationship between the weight on the Moon and on Earth, is a quantitative observation.

(c), watching ice float on water does not involve a measurement; therefore, it must be a qualitative observation.

(d) the fact that we know that the water pump won’t work for depths more than 34 feet makes it quantitative. Again, seeing numbers is a giveaway that it’s a quantitative <span>observation. Quantitative is where you deal with numbers.</span>
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Consider two concentric spheres whose radii differ by t = 1 nm, the "thickness" of the interface. At what radius (in nm) of sphe
Gala2k [10]

Answer:

Radius of the interior sphere = 3.847 nm

Explanation:

The volume of the shell (Vs) is equal to the difference of the volume of the outer sphere (Vo) and the volume of the inner sphere (Vi). Then:

V_s=V_o-V_i=V_i\\V_o=2*V_i\\

If we express the radius of the outer sphere (ro) in function of the radius of the inner sphere (ri), we have (e being the shell thickness):

r_o=r_i+e

The first equation becomes

\frac{4 \pi}{3}*r_o^{3}  = 2 * \frac{4 \pi}{3}*r_i^{3}  \\\\\frac{4 \pi}{3}*(r_i+e)^{3}  = 2 * \frac{4 \pi}{3}*r_i^{3}  \\\\(r_i+e)^{3}  = 2 *r_i^{3}  \\\\(r_i^{3}+3r_i^{2}e+3r_ie^{2}+e^{3})=2r_i^{3}\\\\-r_i^{3}+3r_i^{2}e+3r_ie^{2}+e^{3}=0\\\\-r_i^{3}+3r_i^{2}+3r_i+1=0

To find ri that satisfies this equation we have to find the roots of the polynomial.

Numerically, it could be calculated that ri=3.847 nm satisfies the equation.

So if the radius of the interior sphere is 3.847 nm, the volume of the interior sphere is equal to the volume of the shell of 1nm.

8 0
2 years ago
Hi Please help me, thank you
seropon [69]

Answer:

C I might be wrong tho

Explanation:

3 0
3 years ago
The molecular formula of butane is C4H10. It is obtained from petroleum and is used commonly in LPG (Liquefied Petroleum Gas) cy
seropon [69]

Answer:

See explaination

Explanation:

Please see the attached file for the structural diagram of the molecular formation.

It is detailed and properly presented at the attachment.

8 0
3 years ago
A solution was made by adding water to 0.250 g of H2Z until the volume totaled 25.00 mL. Subsequent titration required 40.50 mL
Brilliant_brown [7]

Answer:

123 g/mol

Explanation:

Let's consider the neutralization reaction.

H₂Z(aq) + 2 NaOH(aq) → Na₂Z(aq) + 2 H₂O(ℓ)

The moles of NaOH that reacted are:

40.50 \times 10^{-3} L \times \frac{0.100molNaOH}{1L} =4.05\times 10^{-3} molNaOH

The molar ratio of H₂Z to NaOH is 1:2. The moles of H₂Z that reacted are:

4.05\times 10^{-3} molNaOH \times \frac{1molH_{2}Z}{2molNaOH} =2.03\times 10^{-3} molH_{2}Z

The molar mass of H₂Z is:

\frac{0.250gH_{2}Z}{2.03\times 10^{-3} molH_{2}Z} =123g/mol

7 0
3 years ago
Hands on mole activity
Amanda [17]

Explanation:

one mole= 6.02x10^23

Everything going from a mole will always be multiplied and everything going into mole will be divided.

4 0
3 years ago
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