Question

You are required to prepare 500 ml of a 6.00 M solution of HNO3 from a stock solution of 12.0 M. Describe in detail how you would go about preparing this solution. Clearly state the volume of stock solution used, the glassware's used and the procedure. ​

Answer 1

Answer: 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

Explanation:

According to the dilution law,

$C_1V_1=C_2V_2$

where,

$C_1$ = concentration of stock solution = 12.0 M

$V_1$ = volume of stock solution = ?

$C_2$ = concentration of diluted solution= 6.00 M

$V_2$ = volume of diluted acid solution = 500 ml

Putting in the values we get:

$12.0\times V_1=6.00\times 500$

$V_1=250ml$

Thus 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.