Answer:
37.5 g of H₂
Explanation:
N₂ (28g) + 3H₂ (6g) => 2NH₃ (34g)
Every 28g of N₂ needs 6g of H₂
=> Every 7g of N₂ needs 1.5g of H₂
=> 175g of N₂ needs 1.5 x 25 g of H₂
=> 37.5 g of H₂
Answer:
Humidity is the amount of moisture (water vapor) in the air. It can be expressed as absolute humidity or relative humidity. Absolute humidity is the mass of water vapor divided by a unit volume of air (grams of water/cm3 of air).
Water is polar meaning that it has prominent areas of negative and positive charge. Among water molecules there is a weak force called hydrogen bonding which causes the molecules to "stick" to one another. This sticking to itself is called cohesion, and it causes water to ball up into droplets. This same force also causes water to stick to other kinds of molecules. This is called adhesion, and it is what causes water to ride up on the side of a water container slightly.
Answer:
The mass of tin is 164 grams
Explanation:
Step 1: Data given
Specific heat heat of tin = 0.222 J/g°C
The initial temeprature of tin = 80.0 °C
Mass of water = 100.0 grams
The specific heat of water = 4.184 J/g°C
Initial temperature = 30.0 °C
The final temperature = 34.0 °C
Step 2: Calculate the mass of tin
Heat lost = heat gained
Qlost = -Qgained
Qtin = -Qwater
Q = m*c*ΔT
m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)
⇒with m(tin) = the mass of tin = TO BE DETERMINED
⇒with c(tin) = the specific heat of tin = 0.222J/g°C
⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C
⇒with m(water) = the mass of water = 100.0 grams
⇒with c(water) = the specific heat of water = 4.184 J/g°C
⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C
m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C
m(tin) = 163.9 grams ≈ 164 grams
The mass of tin is 164 grams
