Answer:
The speed of the car when load is dropped in it is 10.90 m/s.
Explanation:
Given that,
Mass of the railroad car, m₁ = 11600kg
Mass of the load, m₂ = 5420kg
It can be assumed as the speed of the car, u₁ = 16 m/s
Initially, it is at rest, u₂ = 0
The additional load is dropped onto the car.
Let v is the speed of the car. It can be calculated using the conservation of momentum as :
![m_1u_1+m_2u_2=(m_1+m_2)vv=\dfrac{m_1u_1}{m_1+m_2}v=\dfrac{11600\times 16}{11600+5420}v = 10.90 m/s](https://tex.z-dn.net/?f=m_1u_1%2Bm_2u_2%3D%28m_1%2Bm_2%29vv%3D%5Cdfrac%7Bm_1u_1%7D%7Bm_1%2Bm_2%7Dv%3D%5Cdfrac%7B11600%5Ctimes%2016%7D%7B11600%2B5420%7Dv%20%3D%2010.90%20m%2Fs)
So, the speed of the car when load is dropped in it is 10.90 m/s.
Answer:
This immense mountain range began to form between 40 and 50 million years ago, when two large landmasses, India and Eurasia, driven by plate movement, collided. ... Artist's conception of the 6,000-km-plus northward journey of the "India" landmass (Indian Plate) before its collision with Asia (Eurasian Plate).
Explanation:
Answer:
![0.42 m/s^2](https://tex.z-dn.net/?f=0.42%20m%2Fs%5E2)
Explanation:
There are two forces acting on the person as he's standing on the scale in the elevator:
- Its weight,
, downward, with m = 45.0 kg being his mass and g = 9.8 m/s^2 being the acceleration of gravity
- The normal reaction exerted by the scale on the person, N, upward, which is equal to the value read on the scale, N = 460 N
Using Newton's second law, we can write
![N-mg = ma](https://tex.z-dn.net/?f=N-mg%20%3D%20ma)
Where a is the acceleration of the person (and of the elevator). Solving for a,
![a=\frac{N-mg}{m}=\frac{460-(45)(9.8)}{45}=0.42 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BN-mg%7D%7Bm%7D%3D%5Cfrac%7B460-%2845%29%289.8%29%7D%7B45%7D%3D0.42%20m%2Fs%5E2)
And since we chose positive as the upward direction, the acceleration is upward.
Answer:
(B) The number of protons - only the number of protons in the nucleus determines the element - mass and neutrons can vary for the same element