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Nataly_w [17]
3 years ago
11

A 9 cm tall object is placed 16 cm from a converging lens forming an image at 13 cm. What is the height of the image?

Physics
1 answer:
Tresset [83]3 years ago
3 0
The way I actually did that it was just like a little bit of a panic attack and I was like literally dying laughing at my chrome book mark and I was like literally dying laughing at the park I was laughing so loud and I’m literally gonna laughing so I can’t do tell him what he says I don’t think I
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Write down an equation describing a sinusoidal traveling wave (in 1-D). Tell us (words and/or equations) what in your equation t
Natalija [7]

Answer:

Explanation:

The standard equation of the sinusoidal wave in one dimension is given by

y = A Sin\left ( \frac{2\pi }{\lambda }\left ( vt-x \right )+\phi  \right )

Here, A be the amplitude of the wave

λ be the wavelength of the wave

v be the velocity of the wave

Φ be the phase angle

x be the position of the wave

t be the time

this wave is travelling along positive direction of X axis

The frequency of wave is f which relates with velocity and wavelength as given below

v = f x λ

The relation between the time period and the frequency is

f = 1 / T.

6 0
3 years ago
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor = how
UkoKoshka [18]

Answer:

12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.

Explanation:

In the United States, a standard "drink" of beer has 12 ounces, a standard "drink" of wine has 5 ounces and standard drink of liquor has 1.5 ounces. Then, we obtain the quantity of drinks by dividing the total volume of each drink by its respective unit volume and summing each term. That is:

N = \frac{12\,oz}{12\,\frac{oz}{dr} }+\frac{12\,oz}{5\,\frac{oz}{dr} }+\frac{3\,oz}{1.5\,\frac{oz}{dr} }

N = 1\,dr+2.4\,dr+2\,dr

N = 5.4\,dr

N = 6\,dr

12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.

8 0
3 years ago
A cart loaded with bricks has a total mass of 22.2 kg and is pulled at constant speed by a rope. The rope is inclined at 27.5 ◦
musickatia [10]

Answer:

W = 1.432 KJ

Explanation:

given,

mass = 22.2 Kg

angle of the rope = 27.5°

distance on the ground = 24 m

kinetic friction= μ = 0.32

acceleration due to gravity, g = 9.8 m/s²

Work done = ?

W = F d cosθ

a = 0 because it is moving with constant speed

equating all the forces acting  in x direction

F cosθ = F friction = μN  

equating all the forces acting  in y direction

F sinθ + N -mg =0

now,

N = mg - F sinθ

putting value of N

F cosθ = μ mg -μ F sinθ

F (cosθ + μsinθ ) = μ mg

F = \dfrac{\mu mg}{cos\theta + \mu sin\theta}

F = \dfrac{0.32 \times 22.2 \times 9.8}{cos 27.5^0+0.32 \times sin27.5^0}

F =67.28 N

now,

W=F d cosθ

W =67.28 x 24 x cos(27.5)

W =1432.27 J

W = 1.432 KJ

7 0
3 years ago
Read 2 more answers
The stimuli for kinesthesis is the __________ energy of joint and muscle movement. A. thermal B. electrical C. mechanical D. che
lilavasa [31]
The answer to this question is The first option, Or what I should say "A.Thermal"

Your welcome!
4 0
3 years ago
Read 2 more answers
what is the net force of a 6 kg object that goes from a velocity of 0.5 m/s to a velocity of 3 m/s over the course of 1.5 second
baherus [9]

Answer:

∑F = 10.2 N

Explanation:

We have:

Initial velocity: 0.5 m/s

Final velocity: 3 m/s

Time: 1.5 s

We have all of the components needed to calculate acceleration. Let's do that, shall we?

a = vf-vo/t

a = 2.5/1.5

a = 1.7 m/s^{2}

Now, look at the Net Force equation:

∑F = ma

Plug in the variables, to get:

∑F = (6)(1.7)

∑F = 10.2 N (You can round this according to significant digits)

3 0
3 years ago
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