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Nataly_w [17]
3 years ago
11

A 9 cm tall object is placed 16 cm from a converging lens forming an image at 13 cm. What is the height of the image?

Physics
1 answer:
Tresset [83]3 years ago
3 0
The way I actually did that it was just like a little bit of a panic attack and I was like literally dying laughing at my chrome book mark and I was like literally dying laughing at the park I was laughing so loud and I’m literally gonna laughing so I can’t do tell him what he says I don’t think I
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A light beam is traveling through an unknown substance. When it exits that substance and enters into air, the angle of reflectio
bogdanovich [222]

Answer:

0.79

Explanation:

Using Snell's law, we have that:

n(1) * sin θ1 = n(2) * sinθ2

Where n(1) = refractive index of air = 1.0003

θ1 = angle of incidence

n(2) = refractive index of second substance

θ2 = angle of refraction

The angle of reflection through the unknown substance is the same as the angle of incidence of air. This means that θ1 = 32°

=> 1.0003 * sin32 = n(2) * sin42

n(2) = (1.0003 * sin32) / sin42

n(2) = 0.79

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4 years ago
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Which of the following are disadvantages of solar energy? Check all that apply. A. It contributes to global warming. B. It is ex
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B, C, and D.

Solar energy is green energy, it wouldn't contribute to global warming. However some places of the world don't receive as much sunlight (the poles) and at night you don't receive as much sunlight either. Solar energy is also very expensive to farm.
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When a current of 5 amperes is run through the coiled heating element of a stove, the resistance of the element is 80 ohms. What
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Which of the following is true concerning nuclear fusion?
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Choice-a is a very rubbery, imprecise, ambiguous, slippery statement. But it's probably less wrong than any of the other choices on the list.
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As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arr
Nitella [24]

Answer:

  • <u><em>1. Part A: 648N</em></u>
  • <u><em></em></u>
  • <u><em>2. Part B: 324J</em></u>
  • <u><em></em></u>
  • <u><em>3. Part C: 1,296N</em></u>

Explanation:

<em><u>1. Part A:</u></em>

The magnitude of the force is calculated using the Hook's law:

          |F|=k\Delta x

You know \Delta x=0.250m but you do not have k.

You can calculate it using the equation for the work-energy for a spring.

The work done to compress the springs a distance \Delta x is:

          Work=\Delta PE=(1/2)k(\Delta x)^2

Where \Delta PE is the change in the elastic potential energy of the "spring".

Here you have two springs, but you can work as if they were one spring.

You know the work (81.0J) and the length the "spring" was compressed (0.250m). Thus, just substitute and solve for k:

             81.0J=(1/2)k(0.250m)^2\\\\k=2,592N/m

In reallity, the constant of each spring is half of that, but it is not relevant for the calculations and you are safe by assuming that it is just one spring with that constant.

Now calculate the magnitude of the force:

         |F|=k\Delta x=2,592N/m\times 0.250m=648N

<u><em></em></u>

<u><em>2. Part B. How much additional work must you do to move the platform a distance 0.250 m farther?</em></u>

<u><em></em></u>

The additional work will be the extra elastic potential energy that the springs earn.

You already know the elastic potential energy when Δx = 0.250m; now you must calculate the elastic potential energy when  Δx = 0.250m + 0.250m = 0.500m.

          \Delta E=(1/2)2,592n/m\times(0.500m)^2=324J

Therefore, you must do 324J of additional work to move the plattarform a distance 0.250 m farther.

<em><u></u></em>

<em><u>3. Part C</u></em>

<u><em></em></u>

<u><em>What maximum force must you apply to move the platform to the position in Part B?</em></u>

The maximum force is when the springs are compressed the maximum and that is 0.500m

Therefore, use Hook's law again, but now the compression length is Δx = 0.500m

           |F|=k\Delta x=2,592N/m\times 0.500m =1,296N

8 0
3 years ago
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