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GuDViN [60]
3 years ago
6

5. What happens to the inductor current as time passes? 6. What happened to the inductor current when the supply voltage was tri

pled? 7. What happened to the inductor current when the inductor value was doubled? 8. What would be the current if the inductor were allowed to energize indefinitely?
Physics
1 answer:
lawyer [7]3 years ago
6 0

Answer:

i ran out of time

Explanation:

You might be interested in
50 points please help ASAP! !
Contact [7]

Answer:

The sum of the initial and final velocity is divided by 2 to find the average. The average velocity calculator uses the formula that shows the average velocity (v) equals the sum of the final velocity (v) and the initial velocity (u), divided by 2.

4 0
2 years ago
Two resistors, A and B, are connected in series to a 6.0 V battery. A voltmeter connected across resistor A measures a potential
mestny [16]

Answer:

Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

Explanation:

When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.

Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,

V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V

Also, let the current in series be I.

So, V₁ = IR₁ and V₂ = IR₂

I = V₁/R₁ and I = V₂/R₂

equating both expressions, we have

V₁/R₁ = V₂/R₂

4.0 V/R₁ = 2.0 V/R₂

dividing through by 2.0 V, we have

2/R₁ = 1/R₂

taking the reciprocal, we have

R₂ = R₁/2

R₁ = 2R₂

From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V

Also, V₂ = I₂R₂ where I₂ = current in resistor B = 2.0 A and R₂ = resistance of resistor B

So, R₂ = V₂/I₂

= 6.0 V/2.0 A

= 3.0 Ω

R₁ = 2R₂

= 2(3.0 Ω)

= 6.0 Ω

So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

6 0
3 years ago
In a series rlc ac circuit, a second resistor is connected in parallel with the resistor previously in the circuit. as a result
raketka [301]

According to the given statement:

  • The frequency response does not change, which is the first thing we notice.
  • The new resistance at the resonance point causes a reduction in the circuit's current flow.
  •    Z = R + R₂
<h3>The definition of series circuits:</h3>

electrical circuit. The path that the entire current takes as it passes through each component makes up a series circuit. Branching is used in parallel circuits to divide the current and limit the amount that flows through each branch.

<h3>How does a series circuit operate?</h3>

According to this definition, there are three principles of series circuits: all parts share the same current, resistances add up to a larger total resistance, and voltage drops add up to a larger total voltage. In the definition of a series circuit, all of these guidelines have their origin.

<h3>According to the given information:</h3>

The impedance of a series circuit is

       Z₀² = R² + (X_L-X_C) ²

The initial resistance impedance shifts to when we add another resistor to the series

              Z² = (R + R₂) ² + (X_L - X_C) ²

Let's examine this sentence.

  • The frequency response remains unchanged, which is the first thing we notice.
  • The new resistance at the resonance point causes the circuit's current to decrease.

           Z = R + R₂

To know more about electrical circuit visit:

brainly.com/question/1922668

#SPJ4

6 0
1 year ago
Lake point tower in chicago is the tallest apartment building in the united states. suppose you take the elevator from street le
notka56 [123]

Using the idea of work done under gravity, the height of the building is 187 m.

<h3>Work done in a gravitational field</h3>

We must recall that the work done in a gravitational field is given by; mgh

m= mass

g = acceleration due to gravity

h = height

mass = 60.0 kg

Workdone = 1.15x10^5 J

W = mgh

h = W/mg

h =  1.15x10^5 J/60.0 kg * 9.8 ms-2

h = 187 m

Learn more about work done: brainly.com/question/13662169?

7 0
2 years ago
A hockey puck with a mass of 0.159 kg slides over the ice. The puck initially slides with a speed of 4.75 m/s, but it comes to a
Anton [14]

Answer:

The energy dissipated as the puck slides over the rough patch is 1.355 J

Explanation:

Given;

mass of the hockey puck, m = 0.159 kg

initial speed of the puck, u = 4.75 m/s

final speed of the puck, v = 2.35 m/s

The energy dissipated as the puck slides over the rough patch is given by;

ΔE = ¹/₂m(v² - u²)

ΔE = ¹/₂ x 0.159 (2.35² - 4.75²)

ΔE = -1.355 J

the lost energy is 1.355 J

Therefore, the energy dissipated as the puck slides over the rough patch is 1.355 J

5 0
3 years ago
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