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lara31 [8.8K]
3 years ago
11

A cube of wood is floating on water. a cube of iron is totally submerged in water. the cubes are equal in volume. which cube has

the greater buoyant force acting on it?
Physics
1 answer:
-BARSIC- [3]3 years ago
5 0
The one that's completely submerged is displacing more water, so the buoyant force on it is greater.
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Which variable is represented by the following symbol? ∑F
mario62 [17]

Answer:

d.Net force

Explanation:

The net force is the force which is the sum of all the forces acting on an object simultaneously.

5 0
2 years ago
An object is placed 10 cm in front of a diverging mirror. What is the focal length of the mirror if the image appears 2 cm behin
Dafna1 [17]

Answer:

the focal length of the mirror is :  f=-2.5\,\,cm

Explanation:

Use the formula for the formation of image using a divergent mirror and recalling that the image (s') that this mirror formed is virtual, so it is entered as a negative number in the formula. Use the object position (s) as 10, the image position (s') as -2, and derive the value of the focal length:

\frac{1}{s} +\frac{1}{s'}=\frac{1}{f}\\\frac{1}{10} +\frac{1}{-2}=\frac{1}{f}\\\frac{1}{10} -\frac{1}{2}=\frac{1}{f}\\\frac{10\,f}{10} -\frac{10\,f}{2}=\frac{10\,f}{f}\\f-5\,f=10\\-4\,f=10\\f=-2.5\,\,cm

6 0
3 years ago
Determine the total moment of inertia of a merry-go round with 5 children sitting on it. Of the five children, four are seated a
BaLLatris [955]

Answer:

Explanation:

Given that,

We have five children.

Each of mass m =30kg

They sit on a merry go round

Mass of Merry go round M= 150kg

Radius of Merry go round is r =2m

Four children sit at the edge of the merry go round but one child sit at the centre.

The four child that sit at the edge are 2m from the centre of the merry go round but the one at the centre is 0m from the centre

Moment of inertia?

Moment of inertia is given as

I=Σmi•ri²

For the question, the moment of inertia is the combination of inertial of child and the merry go round

I= I(merry go round) + I(four child)+ I(last child)

The merry go round is assumed to be a solid cylinder, so it is going to have the moment of inertia of solid cylinder

Then,

I(merry go round ) =½ Mr²

Also, Four of the child has the same moment of inertia, they are 2m form the centre of the merry go round why the last child has no moment of inertia

I= I(merry go round) + I(four child) +I(last child )

I= ½Mr² + 4mr² + mr'²

I = ½ × 150 ×2² + 4×30×2² + 30×0²

I = 300 +480+0

I = 780 kgm²

7 0
3 years ago
A mass M is hanging from a rope of length L and mass m. A student gives the mass a quick horizontal shake to set up a wave which
disa [49]

Answer:

Explanation:

Expression for velocity of wave produced in a hanging wire can be given  as follows

Velocity v = \sqrt{\frac{T}{m} }

where T is tension in wire and m is mass of wire per unit length.

In the given case

T = Mg + mg

= Mg

neglecting weight of rope

mass of the rope per unit length

= m / L

Velocity of wave

= \sqrt{\frac{Mg}{\frac{m}{L} } }

= \sqrt{\frac{MgL}{m} }

4 0
2 years ago
An amusement park ride raises people high into the air, suspends them for a moment, and then drops them at a rate of free-fall a
blsea [12.9K]

Answer: apparent weighlessness.


Explanation:


1) Balance of forces on a person falling:


i) To answer this question we will deal with the assumption of non-drag force (abscence of air).


ii) When a person is dropped, and there is not air resistance, the only force acting on the person's body is the Earth's gravitational attraction (downward), which is the responsible for the gravitational acceleration (around 9.8 m/s²).


iii) Under that sceneraio, there is not normal force acting on the person (the normal force is the force that the floor or a chair exerts on a body to balance the gravitational force when the body is on it).


2) This is, the person does not feel a pressure upward, which is he/she does not feel the weight: freefalling is a situation of apparent weigthlessness.


3) True weightlessness is when the object is in a place where there exists not grativational acceleration: for example a point between two planes where the grativational forces are equal in magnitude but opposing in direction and so they cancel each other.


Therefore, you conclude that, assuming no air resistance, a person in this ride experiencing apparent weightlessness.

3 0
2 years ago
Read 2 more answers
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