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Murrr4er [49]
2 years ago
13

Arrange the movement/act/organization in ascending order of occurrence. Energy Supply and Environmental Coordination Act Nature

Conservancy Intergovernmental Panel on Climate Change (IPCC) Clean Water Act Federal Water Pollution Control Act Eastern Wilderness Act Water Quality Act Toxic Substances Control Act Clean Air Act Endangered Species Preservation Act ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓
Physics
1 answer:
nadya68 [22]2 years ago
5 0

Answer:

PLATO!!!!! THESE ARE RIGHT!!! OTHERS ARE NOT CORRECT. I JUST GOT IT RIGHT ON PLATO

Explanation:

1. federal water pollution control act

2.nature conservancy

3. clean air act

4. water quality act

5. endangered species preservation act

6. clean water act

7. energy supply and environmental coordination act

8. eastern wilderness act

9. toxic substance act

10. intergovernmental panel on climate change (IPCC).

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A water wave traveling in a straight line on a lake is described by the equation
ivanzaharov [21]

Answer:

A) The wave equation is given as

y(x,t) = A\cos(kx + \omega t)=(3.3\times 10^{-2})\cos(0.004x + 5.05t)\\

According to the above equation, k = 0.004 and ω = 5.05.

Using the following identities, we can find the period of the wave.

\omega = 2\pi f\\ f = 1/ T

T = 1.25 s.

For the horizontal distance travelled by one period of time, x = λ.

\lambda = 2\pi / k = 2\pi / 0.004 = 1.57\times 10^3~m

y(x = \lambda,t = T) = 0.033\cos(0.004*1.57*\10^3 + 5.05*1.25) = 0.033~m

B) The wave number, k = 0.004 . The number of waves per second is the frequency, so f = 0.8.

C) The propagation speed of the wave is

v = \lambda f = 1.57\times 10^3 * 0.8 = 1.256\times 10^3~m/s

The velocity of the wave is the derivative of the position function.

v(x,t) = \frac{dy(x,t)}{dt} = -(5.05\times 0.033)\sin(0.004x + 5.05t)

The maximum velocity is when the derivative of the velocity function is equal to zero.

\frac{dv_y(x,t)}{dt} = -(5.05)^2(0.033)\cos(0.004*1.57\times 10^3 + 5.05t) = 0

In order this to be zero, cosine term must be equal to zero.

0.004*1.57\times 10^3 + 5.05t = 5\pi /2\\t = 0.31~s

The reason that cosine term is set to be 5π/2 is that time cannot be zero. For π/2 and 3π/2, t<0.

v(x=\lambda, t = 0.31) = -(5.05\times0.033)\sin(0.004\times 1.57\times 10^3 + 5.05\times 0.31) = -0.166~m/s

6 0
3 years ago
Which of the following represents a case in which you are not accelerating? -Driving 60 miles per hour around a curve -Going fro
PIT_PIT [208]

Answer:

Driving in a straight line at 60 miles per hour

Explanation:

In the first case there's an acceleration that modifies the direction of the movement.

In the second case there's a lineal acceleration that increases the speed of the car.

in the third case there's a negative acceleration that reduces the speed of the car.

On the third case the speed is constant so the acceleration is 0 mi/s^2

8 0
3 years ago
An electron moving with a velocity = 5.0 × 107 m/s enters a region of space where perpendicular electric and a magnetic fields a
Cloud [144]

Answer:

magnetic field will allow the electron to go through 2 x 10^{4}  T k

Explanation:

Given data in question

velocity = 5.0 × 10^{7}

electric filed = 10^{4}

To find out

what magnetic field will allow the electron to go through, undeflected

solution

we know if electron move without deflection i.e. net force is zero on electron and we can say both electric and magnetic force equal in magnitude and opposite in directions

so we can also say

F(net) = Fe + Fb i.e. = 0

q V B +  q E = 0

q will be cancel out

10^{4}j + 5e + 7i × B =  0

B = 2 x 10^{4}  T k

3 0
3 years ago
Calculate the speed of a satellite moving in a stable circular orbit about the Earth at a height of 4930 km .
svet-max [94.6K]

The speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.

<h3>Speed of the satellite</h3>

v = √GM/r

where;

  • M is mass of Earth
  • G is universal gravitation constant
  • r is distance from center of Earth = Radius of earth + 4930 km

v = √[(6.626 x 10⁻¹¹ x 5.97 x 10²⁴) / ((6371 + 4930) x 10³)]

v = 5,916.36 m/s

Thus, the speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

5 0
1 year ago
A 2.40 cm × 2.40 cm square loop of wire with resistance 1.20×10−2 Ω has one edge parallel to a long straight wire. The near edge
Norma-Jean [14]

Answer:

current in loops is 52.73 μA

Explanation:

given data

side of square a = b  = 2.40 cm = 0.024 m

resistance R = 1.20×10^−2 Ω

edge of the loop c  = 1.20 cm = 0.012 m

rate of current = 120 A/s

to find out

current in the loop

solution

we know current formula that is

current = voltage / resistance    .................a

so current = 1/R × d∅/dt

and we know here that

flux ∅ = ( μ×I×b / 2π ) × ln (a+c/c)    ...............b

so

d∅/dt = ( μ×b / 2π ) × ln (a+c/c) × dI/dt       ...........c

so from equation a we get here current

current = ( μ×b / 2πR ) × ln (a+c/c) × dI/dt

current = ( 4π×10^{-7}×0.024 / 2π(1.20×10^{-2}) × ln (0.024 + 0.012/0.012) × 120

solve it and we get current that is

current = 4 ×10^{-7}× 1.09861 × 120

current = 52.73 ×10^{-6}  A

so here current in loops is 52.73 μA

8 0
2 years ago
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