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kicyunya [14]
3 years ago
14

a magnet has a 20 cm magnetic field if a piece of metal is 18 cm from the magnet will it be attracted or not

Physics
1 answer:
mina [271]3 years ago
4 0

Answer:

yes

Explanation:

The metal is closer than 20 cm to the magnet which is in the magnetic field.

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Considera que en tu casa tienes un televisor de 110 W, si pasa encendido 4 horas diarias, Cuál será la energía consumida durante
rjkz [21]

Answer:

 E = 13.2 kWh

,     Cost = $ 10.8

Explanation:

We can look for the consumed energy from the expression of the power

      P = W / t

The work is equal to the variation of the kinetic energy, for which

       P = E / t

       E = P t

       

look for the energy consumed in one day and multiply by the days of the month in the month

      E = 110 4 30

      E = 13200 W h

       E = 13.2 kWh

the cost of this energy is

    Cost = 0.9 12

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3 years ago
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What is the most commonly used reference point
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Answer:

El punto de referencia más usado es el NORTE. Los puntos de referencia sirven para orientarnos, de esta manera podemos saber nuestra ubicación y luego desplazarnos. En este caso tenemos que el punto cardinal NORTE es el más usado, se tiene como referencia universal para lograr ubicarnos.

Explanation:

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2 years ago
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A +6.33 uC charge q1 is attracted by a force of 0.115 N to a second charge q2 that is 1.44 m away. What is the value of q2?
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Answer:-4.1858

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How does the hydraulic garage lift helps to lift heavy weights?Explain in you words don't copy (write in the easiest way you cou
Sergeeva-Olga [200]

Answer:

this the way that hydraulic pump works:

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Through the suction valves into the two cylinders which creates pressure distributing the fluid equally to the points causing the objects to lift up.

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5 0
2 years ago
The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles
belka [17]

Answer:

F_a=5.67\times 10^{-5}\ N

<u />F_b=3.49\times 10^{-5}\ N

F_c=9.16\times 10^{-5}\ N

Explanation:

Given:

  • mass of particle A, m_a=363\ kg
  • mass of particle B, m_b=517\ kg
  • mass of particle C, m_c=154\ kg
  • All the three particles lie on a straight line.
  • Distance between particle A and B, x_{ab}=0.5\ m
  • Distance between particle B and C, x_{bc}=0.25\ m

Since the gravitational force is attractive in nature it will add up when enacted from the same direction.

<u>Force on particle A due to particles B & C:</u>

F_a=G. \frac{m_a.m_b}{x_{ab}^2} +G. \frac{m_a.m_c}{(x_{ab}+x_{bc})^2}

F_a=6.67\times 10^{-11}\times (\frac{363\times 517}{0.5^2}+\frac{363\times 154}{(0.5+0.25)^2})

F_a=5.67\times 10^{-5}\ N

<u>Force on particle C due to particles B & A:</u>

<u />F_c=G.\frac{m_c.m_b}{x_{bc}^2} +G.\frac{m_c.m_a}{(x_{ab}+x_{bc})^2}<u />

F_c=6.67\times 10^{-11}\times (\frac{154\times 517}{0.25^2}+\frac{154\times 363}{(0.25+0.5)^2} )

F_c=9.16\times 10^{-5}\ N

<u>Force on particle B due to particles C & A:</u>

<u />F_b=G.\frac{m_b.m_c}{x_{bc}^2} -G.\frac{m_b.m_a}{x_{ab}^2}<u />

<u />F_b=6.67\times 10^{-11}\times (\frac{517\times 154}{0.25^2}-\frac{517\times 363}{0.5^2}  )<u />

<u />F_b=3.49\times 10^{-5}\ N<u />

3 0
3 years ago
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