Answer: 2.5 seconds
Explanation:
We know that the acceleration is:
a(t) = 1.7 m/s^2
To get the velocity function, we must integrate over time, and we will get:
v(t) = (1.7m/s^2)*t + v0
Where v0 is the initial velocity, in this case, we assume that we start at 23.6m/s, then the initial velocity is:
v0 = 23.6 m/s
Then the velocity equation is:
v(t) = (1.7m/s^2)*t + 23.6 m/s
Now we want to find the value of t such v(t) = 27.8 m/s
Then:
v(t) = 27.8 m/s = (1.7m/s^2)*t + 23.6 m/s
27.8 m/s - 23.6 m/s = (1.7m/s^2)*t
4.2 m/s = (1.7m/s^2)*t
4.2m/s/(1.7m/s^2) = t = 2.5 s
Then at that acceleration, you need 2.5 seconds.
Answer:
Initial velocity of first cart will be 0.5 m /sec
Explanation:
We have given mass of the cart
Its collides with other cart of mass
Let the initial velocity of cart 1 is
As the car 2 is initially at rest so = 0 m/sec
After the collision velocity of first cart is 0.25 m/sec
So = 0.25 m/sec and velocity of second cart is 0.50 m /sec
So = 0.5 m/sec
From conservation of momentum we know that
= 0.5 m /sec
So initial velocity of first cart will be 0.5 m /sec
Find the volume of the bottom and top separately and then add them.
Cylinder volume is the area of the bottom times the height
(22/7)(5^2)•175=13750 ft^3
The volume of a sphere is
V=(4/3)(22/7)r^3
where r is the radius. Here that's also 5 since it fits on the cylinder.
Also we only want half the sphere so use
V=(2/3)(22/7)•5^3=261.9 ft^3
Which we round upto 262.
Now add the parts together
13750+262=14,012 ft^3
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Hello,
To solve we need to know the formula for speed
The formula is D/T=S (Distance of time=speed)
Now all we have to do is plug in the numbers.
20/40= 1/2 or 0.5
SO the speed is 0.5 m/s
Have a great day!