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GuDViN [60]
2 years ago
5

The statement that "the lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allow

ed by the Pauli principle in a particular set of degenerate orbitals" is known as:
Physics
2 answers:
LUCKY_DIMON [66]2 years ago
8 0

Answer:

Hund's rule

Explanation:

Hund's rule is defined as the rule whose first rule in the chemistry says that, for a given electronic configuration, the term which posses lowest energy has maximum multiplicity. The multiplicity is defined as the tem 2S+1, where S is the total spin angular momentum.

Therefore, the term which has lowest energy that term posses maximum number of S.

Hund's rule of maximum multiplicity: Electron present in same energy orbitals firstly they completed half orbit than start pairing.

Therefore, the energy of lowest configuration for an atom is the one having the maximum number of unpaired electron which is allowed by the Pauli principle in a particular set of degenerate orbit is called Hund's rule.

sashaice [31]2 years ago
6 0

Answer: Hund’s rule

Explanation:

The lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allowed by thePauli principle in a particular set of degenerate orbitals" is known as Hund's rule.

Explanation:

Pauli's Exclusion principle states that "two or more electrons can not have the same values of the set of all quantum numbers in an atom or a molecule".

So, the given statement is not Pauli's Exclusion principle.

Hund's rule states that the lowest energy configuration of an atom is that one in which the maximum number of parallel spins of the electrons are present.

The given statement is "The lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allowed by the Pauli principle in a particular set of degenerate orbitals", which is same as the Hund's rule.

Thus, the given statement is Hund' rule.

Heisenberg's uncertainty principle states that the momentum and position of an object can not be measured exactly at the same time.

So, the given statement is not Heisenberg's uncertainty principle.

Aufbau principle tells about the filling of the electrons in subshells of an atom. Therefore, the given statement is not Aufbau principle.

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8 0
3 years ago
to take off an aircraft carrier, 21000 kg jet needs to accelerate at 36.9 m/s ^2.how much force is required?
user100 [1]
Force = mass times acceleration
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6 0
2 years ago
Read 2 more answers
What is the period of a wave traveling 5 m/s if its wavelength is 20 m/s
Ilia_Sergeevich [38]

Speed of wave is given as

v = 5 m/s

Wavelength of the wave is given as

\lambda = 20 m

now from the formula of wave time period we can say

speed = \frac{wavelength}{time period}

5 = \frac{20}{T}

T = \frac{20}{5}

T = 4 s

so it will have time period of T = 4 s

7 0
3 years ago
A square current-carrying loop is placed in a uniform magnetic field B with the plane of the loop parallel to the magnetic field
Radda [10]

Answer:

(A) a net torque but no net force on the loop.

Explanation:

The total force on the loop is zero because the forces on the opposite sides of the loop are equal but act in opposite directions and as a result they cancel each other out. The two forces on opposite sides to the axis of rotation each give rise to a torque about the axis of rotation. This torque is directed along the axis of rotation.

5 0
3 years ago
A proton moving at 3.0 × 10^4 m/s is projected at an angle of 30° above a horizontal plane. If an electric field of 400 N/C is a
GuDViN [60]

Answer:

The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s

Explanation:

From Newton's second law, F = mg and also from coulomb's law F= Eq

Dividing both equations by mass;

F/m = Eq/m = mg/m, then

g = Eq/m --------equation 1

Again, in a projectile motion, the time of flight (T) is given as

T = (2usinθ/g) ---------equation 2

Substitute in the value of g into equation 2

T = \frac{2usin \theta}{\frac{Eq}{m}} =\frac{m* 2usin \theta}{Eq}

Charge of proton = 1.6 X 10⁻¹⁹ C

Mass of proton = 1.67 X 10⁻²⁷ kg

E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°

Solving for T;

T = \frac{(1.67X10^{-27}* 2*3X10^4sin 30}{400*1.6X10^{-19}}

T = 7.83 X10⁻⁷ s

6 0
2 years ago
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