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GuDViN [60]
2 years ago
5

The statement that "the lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allow

ed by the Pauli principle in a particular set of degenerate orbitals" is known as:
Physics
2 answers:
LUCKY_DIMON [66]2 years ago
8 0

Answer:

Hund's rule

Explanation:

Hund's rule is defined as the rule whose first rule in the chemistry says that, for a given electronic configuration, the term which posses lowest energy has maximum multiplicity. The multiplicity is defined as the tem 2S+1, where S is the total spin angular momentum.

Therefore, the term which has lowest energy that term posses maximum number of S.

Hund's rule of maximum multiplicity: Electron present in same energy orbitals firstly they completed half orbit than start pairing.

Therefore, the energy of lowest configuration for an atom is the one having the maximum number of unpaired electron which is allowed by the Pauli principle in a particular set of degenerate orbit is called Hund's rule.

sashaice [31]2 years ago
6 0

Answer: Hund’s rule

Explanation:

The lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allowed by thePauli principle in a particular set of degenerate orbitals" is known as Hund's rule.

Explanation:

Pauli's Exclusion principle states that "two or more electrons can not have the same values of the set of all quantum numbers in an atom or a molecule".

So, the given statement is not Pauli's Exclusion principle.

Hund's rule states that the lowest energy configuration of an atom is that one in which the maximum number of parallel spins of the electrons are present.

The given statement is "The lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allowed by the Pauli principle in a particular set of degenerate orbitals", which is same as the Hund's rule.

Thus, the given statement is Hund' rule.

Heisenberg's uncertainty principle states that the momentum and position of an object can not be measured exactly at the same time.

So, the given statement is not Heisenberg's uncertainty principle.

Aufbau principle tells about the filling of the electrons in subshells of an atom. Therefore, the given statement is not Aufbau principle.

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3 years ago
A cannon ball is fired directly upward with a velocity of 160 m/s. How long does it take to fall back to the ground? s How fast
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To answer this problem, we will use the equations of motions.

Part (a):
For the ball to start falling back to the ground, it has to reach its highest position where its final velocity will be zero.
The equation that we will use here is:
v = u + at where
v is the final velocity = 0 m/sec
u is the initial velocity = 160 m/sec
a is acceleration due to gravity = -9.8 m/sec^2 (the negative sign is because the ball is moving upwards, thus, its moving against gravity)
t is the time that we want to find.
Substitute in the equation to get the time as follows:
v = u + at
0 = 160 - 9.8t
9.8t = 160
t = 160/9.8 = 16.3265 sec
Therefore, the ball would take 16.3265 seconds before it starts falling back to the ground

Part (b):
First, we will get the total distance traveled by the ball as follows:
s = 0.5 (u+v)*t
s = 0.5(160+0)*16.3265
s = 1306.12 meters
The equation that we will use to solve this part is:
v^2 = u^2 + 2as where
v is the final velocity we want to calculate
u is the initial velocity of falling = 0 m/sec (ball starting falling when it reached the highest position, So, the final velocity in part a became the initial velocity here)
a is acceleration due to gravity = 9.8 m/sec^2 (positive as ball is moving downwards)
s is the distance covered = 1306.12 meters
Substitute in the above equation to get the final velocity as follows:
v^2 = u^2 + 2as
v^2 = (0)^2 + 2(9.8)(1306.12)
v^2 = 25599.952 m^2/sec^2
v = 159.99985 m/sec
Therefore, the velocity of the ball would be 159.99985 m/sec when it hits the ground.
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