A child throws a ball up with an initial velocity of 4
1 answer:
The height of the ball after the given time of motion is 3.275 m.
The given parameters;
- initial velocity of the ball, u = 4 m/s
- height of fall of the ball, h = 2.5 m
- time of motion, t = 0.5 s
The distance traveled by the ball is calculated as follows;
Thus, the height of the ball after the given time of motion is 3.275 m.
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Answer:
The air resistance on the skydiver is 68.6 N
Explanation:
When the skydiver is falling down, there are two forces acting on him:
- The force of gravity, of magnitude , in the downward direction (where m is the mass of the skydiver and g is the acceleration due to gravity)
- The air resistance, , in the upward direction
So the net force on the skydiver is:
where
m = 7.0 kg is the mass
According to Newton's second law of motion, the net force on a body is equal to the product between its mass and its acceleration (a):
In this problem, however, the skydiver is moving with constant velocity, so his acceleration is zero:
Therefore the net force is zero:
And so, we have:
And so we can find the magnitude of the air resistance, which is equal to the force of gravity: