Question

A 60-kg passenger is in an elevator which is initially at rest. The elevator starts to travel downward. It reaches a downward speed of 7m/sec in a time of 4 seconds

Answer 1

Answer:

a. Acceleration = 1.75 m/s²

b. Force = 105 Newton.

Explanation:

Given the following data:

Mass = 60kg

Final velocity = 7m/s

Time = 4 seconds

Required to find the acceleration and force of the body;

a. To find the acceleration;

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Where;

• a is acceleration measured in $ms^{-2}$
• v and u is final and initial velocity respectively, measured in $ms^{-1}$
• t is time measured in seconds.

Since the elevator is starting from rest, its initial velocity is equal to 0m/s.

Substituting into the equation, we have;

$Acceleration = \frac{7 - 0}{4}$

$Acceleration = \frac{7}{4}$

Acceleration = 1.75 m/s²

b. To find the force;

$Force = mass * acceleration$

Substituting into the equation, we have;

$Force = 60 * 1.75$

Force = 105 Newton.