A) if you have a period table handy it’s the number in the top left hand corner of the element
Correction: The temperature change is from 20 °C to 30 °C.
Answer:
Cp = 1.0032 J.g⁻¹.°C⁻¹
Solution:
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 5016 J
m = mass = 500 g
Cp = Specific Heat Capacity = ??
ΔT = Change in Temperature = 30 °C - 20 °C = 10 °C
Solving eq. 1 for Cp,
Cp = Q / m ΔT
Putting values,
Cp = 5016 J / (500 g × 10 °C)
Cp = 1.0032 J.g⁻¹.°C⁻¹
To determine the mass of sucrose from a given volume of solution, we need to convert the volume into mass by using the density of the solution. We calculate as follows:
mass solution = 3.50 ( 1118 ) = 3913 g
mass of sucrose = 3913 g solution ( .485 g sucrose / g solution ) = 1897.805 g sucrose is present in the solution.
The answer is 232 plus 450
