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mel-nik [20]
2 years ago
10

2 differences between ionic and covalent bond.​

Chemistry
1 answer:
hichkok12 [17]2 years ago
8 0

Answer:

Ionic = transfer, covalent = share, ionic is between metal and nonmetal, covalent is between two nonmetals. All of these statements are oversimplifications that have no part in chemistry education.

Actually there is very little difference for real bonds. Essentially all bonds involve some degree of electron sharing. "Ionic" and "covalent" refer to ideal bonds much like we talk about ideal gases and real gases. Real bonds have characteristics of both ideal bond types. Real bonds lie along a continuum with the ideal bond types at either end. The general consensus is that only the bonds between the metals in groups 1 and 2 and the most electronegative nonmetals have substantially high ionic character.

The vast majority of bonds are closer to the middle of the range between the two bond types, with a lot more sharing of electrons than transferring. Indeed, some of the sharing of electrons is somewhat one-sided, with the more electronegative element having a slight negative charge, and the more electropositive element having a slight positive charge. Bonds like this are polar covalent bonds.

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A 100 g sample of potassium chlorate, KCIO3(s), is completely decomposed by heating:
Mama L [17]
Explanation:
In order to be able to calculate the volume of oxygen gas produced by this reaction, you need to know the conditions for pressure and temperature.
Since no mention of those conditions was made, I'll assume that the reaction takes place at STP, Standard Temperature and Pressure.
STP conditions are defined as a pressure of
100 kPa
and a temperature of
0
∘
C
. Under these conditions for pressure and temperature, one mole of any ideal gas occupies
22.7 L
- this is known as the molar volume of a gas at STP.
So, in order to find the volume of oxygen gas at STP, you need to know how many moles of oxygen are produced by this reaction.
The balanced chemical equation for this decomposition reaction looks like this
2
KClO
3(s]
heat
×
−−−→
2
KCl
(s]
+
3
O
2(g]
↑
⏐
⏐
Notice that you have a
2
:
3
mole ratio between potassium chlorate and oxygen gas.
This tells you that the reaction will always produce
3
2
times more moles of oxygen gas than the number of moles of potassium chlorate that underwent decomposition.
Use potassium chlorate's molar mass to determine how many moles you have in that
231-g
sample
231
g
⋅
1 mole KClO
3
122.55
g
=
1.885 moles KClO
3
Use the aforementioned mole ratio to determine how many moles of oxygen would be produced from this many moles of potassium chlorate
1.885
moles KClO
3
⋅
3
moles O
2
2
moles KClO
3
=
2.8275 moles O
2
So, what volume would this many moles occupy at STP?
2.8275
moles
⋅
22.7 L
1
mol
=
64.2 L
6 0
3 years ago
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