Answer:
163.2g
Explanation:
First let us generate a balanced equation for the reaction. This is shown below:
4Al + 3O2 —> 2Al2O3
From the question given, were were told that 3.2moles of aluminium was exposed to 2.7moles of oxygen. Judging by this, oxygen is excess.
From the equation,
4moles of Al produced 2moles of Al2O3.
Therefore, 3.2moles of Al will produce = (3.2x2)/4 = 1.6mol of Al2O3.
Now, let us covert 1.6mol of Al2O3 to obtain the theoretical yield. This is illustrated below:
Mole of Al2O3 = 1.6mole
Molar Mass of Al2O3 = (27x2) + (16x3) = 54 + 48 =102g/mol
Mass of Al2O3 =?
Number of mole = Mass /Molar Mass
Mass = number of mole x molar Mass
Mass of Al2O3 = 1.6 x 102 = 163.2g
Therefore the theoretical of Al2O3 is 163.2g
Answer:3.6 x 101 or 8.77 x 10-1
Answer;
A scalene
Explanation;
A triangle is a geometric figure with three sides and three angles that always add up to 180 degrees.
Based on properties triangles can be classified as equilateral, scalene, isosceles and right triangles.
Equilateral triangles has all the three sides and the angles equal, an isosceles triangle has two of its sides equal, and two angles that are known as the base angles equal. A scalene triangle has all the three angles and sides different from each other. A right triangle is a triangle in which one of the angle is right angle or is 90 degrees.
An isosceles triangle may be a right triangle, equilateral triangle, and also may be an acute triangle, however an isosceles triangle can never be a scalene triangle
The molecular formula : C₁₈H₁₈N₈
<h3>Further explanation</h3>
Given
62.41% C, 5.24% H, and 32.36% N
Required
The molecular formula
Solution
mol ratio
C : 62.41/12.0096 = 5.1967
H : 5.24/1.00784 = 5.1992
N : 32.36/14.0067 = 2.310
Divide by 2.310(smallest)
C : 5.1967/2.31=2.25
H : 5.1992/2.31 = 2.25
N : 2.31/2.31 = 1
Multiplied by 4
C : H : N = 9 : 9 : 4
The empirical formula : C₉H₉N₄
(C₉H₉N₄)n=346.40 g/mol
(12.0096 x 9 + 1.00784 x 9 + 14.0067 x 4)n=346.4
(108.0864+9.07056+56.0268)n=346.4
(173.184)n=346.4
n=2
<em>The molecular formula : C₁₈H₁₈N₈</em>
Charles law states that for a fixed mass of gas at constant pressure the volume of the gas is directly proportional to the temperature in Kelvin scale
v1/T1 = v2/T2
Where v1 is volume and T1 is temperature at the first instance
v2 is volume and T2 is temperature at the second instance
Substituting the values in the equation
0.5 L / 203 K = v2 / 273 K
v2 = 0.672 L
The volume of Air after heating is 0.672 L
