Question

I need help asap!!!!

Answer 1

Answer:

24.64 L of O2 will be produced

Explanation:

Step 1: Data given

Mass of hydrogen peroxide = 75.0 grams

Molar mass of hydrogen peroxide (H2O2) = 34.015 g/mol

Step 2: The balanced equation

2H2O2 → 2H2O + O2

Step 3: Calculate moles H2O2

Moles H2O2 = 75.0 grams / 34.015 g/mol

Moles H2O2 = 2.20 moles

Step 4: Calculate moles O2

For 2 moles H2O2 we'll have 2 moles H2O and 1 mol O2

For 2.20 moles H2O2 we'll have 2.20/2 = 1.10 moles O2

Step 5: Calculate volume of O2

For 1 mol we have 22.4 L

For 1.10 moles we have 1.10 * 22.4 L = 24.64 L

24.64 L of O2 will be produced

Answer 2

Answer:

2H₂O₂ →  2H₂O + O₂

24.7 L are the liters of formed oxygen.

Explanation:

We state the reaction:

2H₂O₂ →  2H₂O + O₂

2 moles of peroxide decompose to 2 moles of water and 1 mol of oxygen gas.

We convert the mass to moles: 75 g . 1 mol / 34 g = 2.20 moles

As ratio is 2:1, per 2.20 moles of peroxide I would produce the half of moles, of O₂ → 2.20 /2 = 1.10 moles

We convert the moles to mass → 1.10 mol . 32 g / 1 mol = 35.3 g

Let's use oxygen's density to find out the volume

δ O₂ = 1.429 g/L    (mass/volume)

35.3 g . 1L / 1.429g = 24.7 L