4 years ago

How far is a spring extended if it has 1.0 j of potential energy and its spring constant is 1,000 n/m?

Physics

1 answer:

DerKrebs [107]4 years ago

3 0

E=F*d/2 = k*d * d/2 =>
d^2= 2*E/k

d= sqrt(2*E/k)=sqrt(2*1J/1000N/m)=sqrt(20m^2)/100=0.045 m = 45 mm

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Explanation:

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