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Digiron [165]
3 years ago
12

Identify the combustion reaction. identify the combustion reaction. c(s) + o2(g) → co2(g) 2 h2(g) + o2(g) → 2 h2o(g) c3h8(g) + 5

o2(g) → 3 co2(g) + 4 h2o(g) 2 c3h7oh(l) + 9 o2(g) → 6 co2(g) + 8 h2o(g) all of the reactions are examples of combustion reactions.
Chemistry
1 answer:
tester [92]3 years ago
7 0
Combustion reaction occurs when organic compound reacts with oxygen to form CO₂, H₂O and energy
C(s) + O₂(g) → CO₂(g) is Synthesis reaction not combustion
2 H₂(g) + O₂(g) → 2 H₂O(g) also Synthesis reaction and not combustion
C₃H₈(g) + 5 O₂ → 3 CO₂(g) + 4 H₂O(g) is considered as Combustion reaction
2 C₃H₇OH(l) + 9 O₂(g) → 6 CO₂(g) + 8 H₂O(g) Combustion reaction
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Which element is reduced in the following reaction: 2Mg+O₂ → 2MgO if Mg goes from 0 to +2 and O goes from 0 to -2?
Lyrx [107]

Answer:

O.

Explanation:

  • The element which is oxidized is the element that losses electrons and its oxidation state be more positive.
  • The element which is reduced is the element that gain electrons and its oxidation state be more negative.

<em> O goes from 0 to -2, so, it is the element that is reduced.</em>

8 0
2 years ago
Strontium sulfate becomes less soluble in an aqueous solution when sodium sulfator is added because
horsena [70]

Answer:

The addition of sulfate ions shifts equilibrium to the left.

Explanation:

Hello!

In this case, according to the following ionization of strontium sulfate:

SrSO_3(s)\rightleftharpoons Sr^{2+}+SO_4^{2-}

It is evidenced that when sodium sulfate is added, sulfate, SO_4^{2+} is actually added in to the solution, which causes the equilibrium to shift leftwards according to the Le Ch athelier's principle. Thus, the answer in this case would be:

The addition of sulfate ions shifts equilibrium to the left.

Best regards!

7 0
2 years ago
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Use the periodic table to write the electron configuration of selenium (Se). s s p d 1 2 3 4 6 10
maw [93]

Answer: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^4

Explanation:

I suggest looking at the electron configuration chart, it has really helped me a lot :)

4 0
2 years ago
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A sample of neon gas occupies a volume of 752ml at 25k. What volume will the gas occupy at 80k if the pressure remains constant
Anettt [7]

Answer:

The gas occupy 2406.4 mL at 80 K.

Explanation:

Given data:

Initial volume of gas = 752 mL

Initial temperature = 25 K

Final temperature = 80 K

Final volume = ?

Solution:

The given problem is solved by using charle's law.

V₁/T₁ = V₂/T₂

V₂ =  V₁. T₂ /T₁

V₂ = 752 mL × 80 k / 25 K

V₂ = 60160 mL. k/25 K

V₂ =  2406.4 mL

7 0
2 years ago
What is the most abundant metalloid in the universe
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