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3 years ago

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A coil of wire consists of 20 turns, each of which has an area of 0.0015 m2. A magnetic field is perpendicular to the surface wi

th a magnitude of B 4.91 T/s t- 5.42 T/s2 t2. What is the magnitude of the induced emf in the coil?

1 answer:

stepan [7]3 years ago

7 0

Answer:

magnitude of the induced emf in the coil is 0.0153 V

Explanation:

Given data

no of turns = 20

area = 0.0015 m²

magnitude B1 = 4.91 T/s

magnitude B2 = 5.42 T/s

to find out

the magnitude of the induced emf in the coil

solution

we know here

emf = -n A d∅ /dt

so here n = 20 and

A = 0.0015

and d∅ = B2 - B1 = 5.42 - 4.91

d∅ = 0.51 T and dt at 1 sec

so put all value

emf = -n A d∅ /dt

emf = -20 (0.0015) 0.51 / 1

emf = - 0.0153

so magnitude of the induced emf in the coil is 0.0153 V

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