1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naddik [55]
3 years ago
6

A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds

of its travel. What is
its average speed during the time from t = 5 seconds to t = 10 seconds?
ОА.
2 meters/second
B.
3 meters/second
C.
4 meters/second
D.
5 meters/second
E.
6 meters/second
Physics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

A body travels 10 meters during the first 5 seconds of its travel,and a total of 30 meters over the first 10 seconds of its travel

20miles / 5sec = 4miles /sec would be the average speed for the last 20 m

Explanation:

The answer is 4 m/s.

In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).

The relation of speed (v), distance (d), and time (t) can be expressed as:

v = d/t

We need to calculate the speed of the second 5 seconds of the travel:

d = 20 m (total 30 meters - first 10 meters)

t = 5 s (time from t = 5 seconds to t = 10 seconds)

Thus:

v = 20m / 5s = 4 m/s

PLEASE GIVE BRAINIEST!! HOPE THIS HELPS

You might be interested in
With what initial velocity must an object be thrown upward from a height of 2 meters to reach a maximum hieght of 200 meters
larisa86 [58]
The equations of motion to use for a constant acceleration a = g = -9.81:
v = gt + v_0
y = \frac{1}{2} g t^{2} + v_0t + y_0

at the highest point the velocity must be zero:
0 = gt + v_0 \\ v_0 = -gt
combine both equations:
y =  \frac{1}{2}  \frac{v_0^{2} }{g}  -   \frac{v_0^{2} }{g}  + y_0=  -\frac{1}{2}  \frac{v_0^{2} }{g} + y_0
Solve for v₀:
v_0 =   \sqrt{2g(y_0 - y)}
6 0
3 years ago
What is true about all scientists
zlopas [31]
All scientists on Earth are human beings. That's the only thing you can say that applies to ALL of them.
8 0
3 years ago
The density of ice is 0.93 g/cm3. what is the volume, in cm3, of a block of ice whose mass is 5.00 kg? remember to select an ans
serious [3.7K]

The Volume of the ice block is 5376.344 cm^3.

The density of a material is define as the mass per unit volume.

Here, the density of ice given is 0.93 g/cm^3

Mass of the ice block  given is 5 kg or 5000 g

Now calculate the volume of the ice block

density=mass/volume

0.93=5000/Volume

Volume =5376.344 cm^3

Therefore the volume of  ice block is 5376.344 cm^3

7 0
3 years ago
A girl of mass m1=60 kilograms springs from a trampoline with an initial upward velocity of v1=8.0 meters per second. At height
AleksandrR [38]

a) 5.0 m/s

This first part of the problem can be solved by using the conservation of energy. In fact, the mechanical energy of the girl just after she jumps is equal to her kinetic energy:

E_i=\frac{1}{2}m_1v_1^2

where m1 = 60 kg is the girl's mass and v1 = 8.0 m/s is her initial velocity.

When she reaches the height of h = 2.0 m, her mechanical energy is sum of kinetic energy and potential energy:

E_f = \frac{1}{2}m_1 v_2 ^2 + m_1 gh

where v2 is the new speed of the girl (before grabbing the box), and h = 2.0m. Equalizing the two equations (because the mechanical energy is conserved), we find

\frac{1}{2}m_1 v_1^2 = \frac{1}{2}m_1 v_2 ^2 + m_1 gh\\v_1^2 = v_2^2 +2gh\\v_2 = \sqrt{v_1^2 -2gh}=\sqrt{(8.0 m/s)^2-(2)(9.8 m/s^2)(2.0 m)}=5.0 m/s

b) 4.0 m/s

After the girl grab the box, the total momentum of the system must be conserved. This means that the initial momentum of the girl must be equal to the total momentum of the girl+box after the girl catches the box:

p_i = p_f\\m_1 v_2 = (m_1 + m_2) v_3

where m2 = 15 kg is the mass of the box. Solving the equation for v3, the combined velocity of the girl+box, we find

v_3 = \frac{m_1 v_2}{m_1 + m_2}=\frac{(60 kg)(5.0 m/s)}{60 kg+15 kg}=4 m/s

c) 2.8 m

We can use again the law of conservation of energy. The total mechanical energy of the girl after she catches the box is sum of kinetic energy and potential energy:

E_i = \frac{1}{2}(m_1+m_2) v_3^2 + (m_1+m_2)gh=\frac{1}{2}(75 kg)(4 m/s)^2+(75 kg)(9.8 m/s^2)(2.0m)=2070 J

While at the maximum height, the speed is zero, so all the mechanical energy is just potential energy:

E_f = (m_1 +m_2)gh_{max}

where h_max is the maximum height. Equalizing the two expressions (because the mechanical energy must be conserved) and solving for h_max, we find

E_i = (m_1+m_2)gh_{max}\\h_{max}=\frac{E_i}{(m_1+m_2)g}=\frac{2070 J}{(75 kg)(9.8 m/s^2)}=2.8 m

4 0
3 years ago
Why does Mars not have an electric field and why
tangare [24]

Answer:

The difference lies in the planets' respective magnetic fields, because while Earth's magnetism comes from within, Mars' does not. Earth's magnetism comes from its core, where molten, electrically conducting iron flows beneath the crust. Its magnetic field is global, meaning it surrounds the entire planet

Explanation:

thanks for question

7 0
3 years ago
Other questions:
  • A small segment of wire contains 10 nC of charge. The segment is shrunk to one-third of its original length. A proton is very fa
    10·1 answer
  • An ocean liner is cruising at 10 meters/second and is about to approach a stationary ferryboat. A parcel is released from the oc
    9·1 answer
  • 3. A clown rides a small car at a speed of
    15·1 answer
  • A 4-m long wire with a mass of 70 g is under tension. A transverse wave for which the frequency is 300 Hz, the wavelength is 0.6
    7·1 answer
  • If a = 7 × 10−6 C/m4 and b = 1 m, find E at r = 0.6 m. The permittivity of a vacuum is 8.8542 × 10−12 C 2 /N · m2 . Answer in un
    12·1 answer
  • In Hans Oersted’s experiment, why did a compass needle move when an electric current flowed through a nearby wire?
    5·2 answers
  • The number 0.00325 × 10-8 cm can be expressed in millimeters as A) 3.25 × 10-11 mm. B) 3.25 × 10-10 mm. C) 3.25 × 10-12 mm. D) 3
    10·1 answer
  • A elephant kicks a 5.0 kg stone with 150 J of kinetic energy.
    11·1 answer
  • Caillou wait no what
    5·2 answers
  • Tell your best joke or get L bozo​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!