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3 years ago

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A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds

of its travel. What is
its average speed during the time from t = 5 seconds to t = 10 seconds?
ОА.
2 meters/second
B.
3 meters/second
C.
4 meters/second
D.
5 meters/second
E.
6 meters/second

1 answer:

Inessa05 [86]3 years ago

5 0

Answer:

A body travels 10 meters during the first 5 seconds of its travel,and a total of 30 meters over the first 10 seconds of its travel

20miles / 5sec = 4miles /sec would be the average speed for the last 20 m

Explanation:

The answer is 4 m/s.

In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).

The relation of speed (v), distance (d), and time (t) can be expressed as:

v = d/t

We need to calculate the speed of the second 5 seconds of the travel:

d = 20 m (total 30 meters - first 10 meters)

t = 5 s (time from t = 5 seconds to t = 10 seconds)

Thus:

v = 20m / 5s = 4 m/s

PLEASE GIVE BRAINIEST!! HOPE THIS HELPS

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$\texttt{ }$

<h3>Further explanation</h3>

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$\texttt{ }$

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$\texttt{ }$

<h3>Step B:</h3>

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<h3>Answer details</h3>

Grade: High School

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