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Archy [21]
3 years ago
7

Oxygen 22 has a half life of 2.25 seconds. What percent of the sample is left after 2.25 seconds?

Chemistry
2 answers:
Nonamiya [84]3 years ago
6 0

Answer:

50 because it’s a ratio problem

Explanation:

serg [7]3 years ago
3 0

Answer:

So we got 50% left after 2.25 seconds

Explanation:

The left sample is given by

m=m_{0}.2^\frac{-t}{T}

where T is the half-life

After 2.25 s

m=m_{0}.2^\frac{-2.25}{2.25}=m_{0}.\frac{1}{2}

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3 years ago
A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr
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184.62 ml

Explanation:

Let p_1, v_1, and T_1 be the initial and p_2, v_2, and T_2 be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

p_1=p_2 ...(i)

v_1 = 200 ml

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T_2= 3 ^{\circ}C = 273+3 =276 K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)

For the final condition,

p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)

Equating equation (i), and (ii)

\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}

\frac{v_1}{T_1}=\frac{v_2}{T_2}  [from equation (i)]

v_2=\frac{T_2}{T_1} \times v_1

Putting all the given values, we have

v_2=\frac{276}{299} \times 200 = 184.62 \; ml

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

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2 years ago
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