What is the chemical test for chlorine?

A nuclear power plant operates at 40.0% efficiency with a continuous production of 1042 MW of usable power in 1.00 year and cons

Sergio039 [100]

Answer:

3.00 x 10^-11 joules / atom of U-235

Explanation:

We know that the formula for Power = Work done (w)/Time (t)

We need to get the joules from power , since Joules is the SI unit of work.

From the formula P = W/t

W = Power (P) * Time (t)

The SI unit for Time is seconds, hence we change 1 year in seconds

1yr * 365 days/yr * 24hrs/day * 60mins/hr * 60 secs/min = 31536000 secs

It was stated in the question that the plant operates at an efficiency of 40%,

Thus to get the true power we divide the power provided in the question by 0.4 or 40%

= X(0.4) = 1042MW

True Power X = 1042/0.4 = 2605MW

Thus true power = 2605 * 10^6 Watts

Now we have the time in seconds and true power in Watts, we then find the work done.

From our above formula P = W/t

W = P*t = (2605* 10^6) (31536000) =

Finally, we can solve for our energy (work):

P = W / T PT = W = (2880x10^6) (31536000) = 8.22 x 10^16 joules

We then calculate the amount of energy released by only 1 single uranium-235 atom.

= 8.22 x 10^16 joules / 1.07x10^6 g U-235 (235 g / 1 mol)(1 mol/6.0210^23 atoms)

= 3.00 x 10^-11 joules / atom of U-235

5 0

3 years ago

Question 1

nordsb [41]

#1 B

#2 C

#3 B

#4 A.

I Just did this

8 0

2 years ago

Calculate the approximate number of atoms in a bacterium, assuming the average mass of an atom is ten times the mass of a hydrog

mezya [45]

Answer: -

The approximate number of atoms in a bacterium is 10¹¹

Explanation: -

We are given the mass of a bacterium is 10⁻¹⁵ kg.

We are told that the mass of a hydrogen atom is 10⁻²⁷ kg.

Finally we learn that the average mass of an atom of the bacterium is ten times the mass of a hydrogen atom.

Mass of an atom of bacterium = 10 x mass of hydrogen atom

= 10 x 10⁻²⁷ kg.

= 10⁻²⁶ kg.

Thus the number of atoms in a bacterium = $\frac{Total mass}{mass of 1 bacterium atom}$

= $\frac{10-15 kg}{10-26 kg}$

= 10¹¹

8 0

3 years ago

Describe how you would create a model of sea-floor spreading using everyday materials

Elodia [21]

Answer:

Take a cardboard, cylinder-shaped container and cut a vertical slit about 3 ½ inches long and ¼ inch wide down the side. The slit is your mid-ocean ridge, the place where the plates are moving away from each other.

Cut a piece of white paper in half lengthwise.

On each piece of paper, measure two inches in from the end and fold the paper so that there is a section on each end to hold onto.

Measure inward another two inches from the fold, and color in that two-inch wide strip.

Continue to measure in two-inch segments, coloring every other section.

Place the unfolded ends of the paper into the slit in the container. Holding them by the folds, pull the pieces of paper out again. If you imagine that the slit is the midocean ridge where the plates are moving away from each other, the paper is the new liquid rock coming out from the ridge. The first bit of paper to come out is the oldest rock, and the last section of paper to come out is the youngest. Imagine that your paper goes on forever. Soon, the first bit you took out of the hole will be far away from the midocean ridge. Of course, “soon” in geological time is a very long time in human terms!

Take your pieces of paper and tape the ends that aren’t folded to the pencil.

Put the pencil inside of the container and pull the ends of the pieces of paper up through the slit.

Twist the pencil one way, and the papers will move out and away from each other. This is what happens at a divergent plate boundary on the mid-ocean ridges.

Twist the pencil the other way, and the papers will move in and toward each other. This is what happens at a convergent plate boundary. Imagine what would happen if those papers had bumps on them. They’d get all bunched together at the hole, and create mountains.

Explanation:

4 0

3 years ago

How many milliliters of 0.50 M KOH are needed

spayn [35]

Answer:

Option D. 30 mL.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above,

The mole ratio of the acid, nA = 1

The mole ratio of the base, nB = 1

Step 2:

Data obtained from the question. This include the following:

Volume of base, KOH (Vb) =.?

Molarity of base, KOH (Mb) = 0.5M

Volume of acid, HNO3 (Va) = 10mL

Molarity of acid, HNO3 (Ma) = 1.5M

Step 3:

Determination of the volume of the base, KOH needed for the reaction. This can be obtained as follow:

MaVa / MbVb = nA/nB

1.5 x 10 / 0.5 x Vb = 1

Cross multiply

0.5 x Vb = 1.5 x 10

Divide both side by 0.5

Vb = (1.5 x 10) /0.5

Vb = 30mL

Therefore, the volume of the base, KOH needed for the reaction is 30mL.

3 0

3 years ago