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fredd [130]
3 years ago
10

NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics
2 answers:
gulaghasi [49]3 years ago
7 0

Answer:

It would be cooler I believe

Explanation:

Delicious77 [7]3 years ago
6 0

Answer:

warmer

Explanation:

I really think it just gets hot

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Calculate the magnitude and direction of the electric field 2.0 m from a long wire that is charged uniformly at λ = 4.0 × 10-6 C
Len [333]

Answer: 71.93 *10^3 N/C

Explanation: In order to calculate the electric field from long wire we have to use the Gaussian law, this is:

∫E*dr=Q inside/εo  Q inside is given by: λ*L then,

E*2*π*r*L=λ*L/εo

E= λ/(2*π*εo*r)= 4* 10^-6/(2*3.1415*8.85*10^-12*2 )= 71.93 * 10^3 N/C

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3 years ago
Identify the name of the most common substance found in the Ocean​
katen-ka-za [31]

Answer:

Explanation:

Salt

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3 years ago
During a blackout, you are trapped in a tall building. you want to call rescuers on your cell phone, but you can't remember whic
Gennadij [26K]

Let the height where we are trapped is H

now to find the time to reach the key at the bottom is given as

y = v_i t + \frac{1}{2}at^2

now we have

H = \frac{1}{2}gt^2

t = \sqrt{\frac{2H}{g}}

now if the speed of sound is considered to be 340 m/s then time taken by the sound to reach at the top is given as

t = \frac{H}{340}

now the total time is given as

\sqrt{\frac{2H}{g}} + \frac{H}{340} = 3.27

now by solving above equation we have

H = 48 m

now height of one floor is 3 m

so our position must be

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3 0
3 years ago
If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2
kaheart [24]

Answer:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

So then the difference of temperature across the material would be \Delta T = 375 K

Explanation:

For this case we can use the Fourier Law of heat conduction given by the following equation:

Q = -kA \frac{\Delta T}{\Delta x}   (1)

Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 represent the cross sectional area

Q= 3KW represent the rate of heat transfer

\Delta T is the temperature of difference that we want to find

\Delta x=2.5 cm =0.025 m represent the thickness of the material

If we solve \Delta T in absolute value from the equation (1) we got:

\Delta T =\frac{Q \Delta x}{Ak}

First we convert 3KW to W and we got:

Q= 3 KW* \frac{1000W}{1 Kw}= 3000 W

And we have everything to replace and we got:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

So then the difference of temperature across the material would be \Delta T = 375 K

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