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Molodets [167]
3 years ago
13

A person 1.8m tall stands 0.75m from a reflecting globe in a garden.

Physics
1 answer:
Maru [420]3 years ago
6 0

Answer:

1. The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.

2. The person's image is 3.38 m tall.

Explanation:

From the given question, object distance, u = 0.75 m, object height = 1.8 m, radius of curvature of the reflecting globe, r = 8 cm = 0.08 m.

f = \frac{r}{2} = \frac{0.08}{2} = 0.04 m

1. The image distance, v, can be determined by applying mirror formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

\frac{1}{0.04} = \frac{1}{0.75} + \frac{1}{v}

\frac{4}{100} - \frac{75}{100} = \frac{1}{v}

\frac{1}{v} = \frac{4 - 75}{100}

  = - \frac{71}{100}

⇒ v = -\frac{100}{71}

      = - 1.41 m

The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.

2.  \frac{image distance}{object distance} = \frac{image height}{object height}

  \frac{1.41}{0.75} = \frac{v}{1.8}

v = \frac{2.538}{0.75}

  = 3.384

v = 3.38 m

The person's image is 3.38 m tall.

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Now, using tan\theta = \frac{1}{m} and y = 1 in the above eqn, we get:

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Answer:

M₀ = 5i - 4j - k

Explanation:

Using the cross product method, the moment vector(M₀) of a force (F) is about a given point is equal to cross product of the vector A from the point (r) to anywhere on the line of action of the force itself. i.e

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From the question,

r = i + j + k

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M₀ = (i + j + k) x (1i + 0j +  5k)

M₀ = \left[\begin{array}{ccc}i&j&k\\1&1&1\\1&0&5\end{array}\right]

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