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Molodets [167]
3 years ago
13

A person 1.8m tall stands 0.75m from a reflecting globe in a garden.

Physics
1 answer:
Maru [420]3 years ago
6 0

Answer:

1. The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.

2. The person's image is 3.38 m tall.

Explanation:

From the given question, object distance, u = 0.75 m, object height = 1.8 m, radius of curvature of the reflecting globe, r = 8 cm = 0.08 m.

f = \frac{r}{2} = \frac{0.08}{2} = 0.04 m

1. The image distance, v, can be determined by applying mirror formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

\frac{1}{0.04} = \frac{1}{0.75} + \frac{1}{v}

\frac{4}{100} - \frac{75}{100} = \frac{1}{v}

\frac{1}{v} = \frac{4 - 75}{100}

  = - \frac{71}{100}

⇒ v = -\frac{100}{71}

      = - 1.41 m

The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.

2.  \frac{image distance}{object distance} = \frac{image height}{object height}

  \frac{1.41}{0.75} = \frac{v}{1.8}

v = \frac{2.538}{0.75}

  = 3.384

v = 3.38 m

The person's image is 3.38 m tall.

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If you measured 25 g jelly beans and 25 g of gumdrops, the number of jellybeans would be
KengaRu [80]

The number of jellybeans would be B.more than the gumdrops.

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7 0
3 years ago
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Heather and Matt take 34 minutes to walk eastward along a straight road to a store 2.0km away. What is their average velocity in
frez [133]

Their average velocity is 0.98 m/s east.

Explanation:

The average velocity of an object is defined as the ratio between the displacement and the time taken:

v=\frac{displacement}{time}

The displacement is a vector connecting the initial point to the final point of motion: so, being displacement a vector, velocity is a vector as well, having the same direction of displacement.

Here, Heather and Matt walk 2.0 km eastward, so their displacement is

d = 2.0 km = 2000 m (east)

While the time they took is

t=34 min \cdot 60 = 2040 s

Therefore, their average velocity is

v=\frac{2000}{2040}=0.98 m/s

And the direction is the same as the displacement (east).

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brainly.com/question/5248528

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7 0
3 years ago
A hard-boiled egg of mass 46.0 gg moves on the end of a spring with force constant 25.6 N/mN/m . The egg is released from rest a
soldi70 [24.7K]

Answer:

0.022kg/s

Explanation:

We are given that

Mass of boiled egg=46 g=\frac{46}{1000} kg=0.046 kg

1kg=1000 g

Constant force=F=25.6 N/m

Initial displacement=A_1=0.296 m

Final displacement=A_2=0.12 m

Time=t=4.55 s

Damping force=F_x=-bv_x

We have to find the  magnitude of damping constant b.

We know that the displacement of the oscillator under damping motion is given by

x=Ae^{-\frac{b}{2m}t}cos(w't+\phi)

For maximum displacement cos(w't+\phi)=1

Therefore , x=A_2

Substitute the values

A_2=A_1e^{-\frac{-b}{2m}t}

e^{-\frac{b}{2m}t}=\frac{A_2}{A_1}

-\frac{b}{2m}t=ln\frac{A_2}{A_1}

lnx=y\implies x=e^y

Substitute the values

-\frac{b}{2\times 0.046}\times 4.55=ln\frac{0.12}{0.296}

\frac{2\times 0.046}{4.55b}=ln\frac{0.296}{0.12}

\frac{2\times 0.046}{4.55}=0.9b

b=\frac{2\times 0.46}{4.55\times 0.9}=0.022kg/s

Hence,the  magnitude of damping constant b=0.022kg/s

3 0
3 years ago
(answer the question or get reported) Please solve it with the steps thanks :)​
DaniilM [7]

Answer:

Fx = 35.36 N

Fy = 35.36 N

Explanation:

From the question,

The X component of the force is

Fx = Fcos∅.................. Equation 1

Where Fx = X component of the force, F = Force, ∅ = Angle to the horizontal.

Give: F = 50 N, ∅ = 45°

Substitute into equation 1

Fx = 50(cos45°)

Fx = 50(0.7071)

Fx = 35.36 N

Similarly,

For Y component

Fy = Fsin∅

Where F y = Y component

Fy = 50(sin45°)

Fy = 50(0.7071)

Fy = 35.36 N

4 0
2 years ago
Determine the lamp wattage required to obtain an illumination level of 50 f-c over a 100 ft2 area if a fixture is used with a CU
Bezzdna [24]

Lamp Wattage is utilized with a CU of 0.75 and 80 percent of the available light reaches the work surface, the remaining 20 percent is absorbed by walls and other objects in the space, resulting in an illumination level of 50 f-c over a 100 ft2 area

The term "lumen" refers to the emission of "luminous flux," which is a measurement of the total amount of visible light emitted by a source in a certain amount of time. The illumination level over a 100 ft2 area will be 50 f-c Lamp Wattage with a CU of 0.75 used, with 80 percent of the available light reaching the work surface and the remaining 20 percent being absorbed by walls and other objects in the room.
Total Lamp Wattage = Number of Lamps X Wattage of Each Lamp.
The fixtures' total wattage is 2 x 32, or 64 watts.
Lumen per Fixtures equals Lumen Efficiency (Lumen per Watt) times the Watt of each Fixture
85x 64 = 5440 lumens per fixture.

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