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Ipatiy [6.2K]
3 years ago
13

Which object is least likely to allow light to pass through it?

Physics
2 answers:
Zarrin [17]3 years ago
8 0

Answer: The correct option is "a tree trunk".

Explanation:

Transparent is a material which allows the light to pass through it.

For example, glass.

An opaque is a material which does not allow light to pass through it.

For example, wood.

Translucent is a material which allows light partially to pass through it.

For example, butter paper.

In the given options, a pair of eyeglasses, a clear water bottle, a car windshield are transparent materials. But a tree trunk is an opaque as it does not light to pass through it.

Therefore, a tree trunk is least likely allow light to pass through it.

jeka57 [31]3 years ago
6 0

a tree truck

is the answer i hope this helps you xD


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Two large thin metal plates are parallel and close to each other. On their inner faces, the plates have excess surface charge of
wariber [46]

Answer:

For left = 0  N/C

For right = 0  N/C

At middle = -7.6836 * 10^{-11} \vec{i}  N/C

Explanation:

Given data :-

б =6.8 * 10^{-22} C/ m²

Considering the two thin metal plates to be non conducting sheets of charges.

Electric field is given by

E = \frac{\sigma }{2\varepsilon }

1) To the left of the plate

\vec{E}= (\frac{\sigma }{2\varepsilon })(-\vec{i})+  (\frac{\sigma }{2\varepsilon })(\vec{i})   = 0 N/C.

2) To the right of them.

\vec{E}= (\frac{\sigma }{2\varepsilon })(-\vec{i})+  (\frac{\sigma }{2\varepsilon })(\vec{i})   = 0 N/C.

3) Between them.

\vec{E}= (\frac{\sigma }{2\varepsilon })(-\vec{i})+  (\frac{\sigma }{2\varepsilon })(-\vec{i}) = (\frac{\sigma }{\varepsilon })(-\vec{i}) = -\frac{6.8 * 10^{-22} }{8.85 * 10 ^{-12} }  \vec{i} =   -7.6836 * 10^{-11} \vec{i} N/C

5 0
3 years ago
Knowing the causes of respiratory system diseases, what are
Kamila [148]
Cover your cough
Wash your hands
Keep a clean space
Avoid smoking
Stay active

Hope this helps :)
8 0
4 years ago
Why will a delivery truck filled with birds sitting on its floor be heavier than a truck with the same birds flying around insid
34kurt

The reason why a delivery truck filled with birds sitting on the floor be heavier than a truck with the same birds flying around is because when the birds are sitting on the floor, they are adding their weight to the truck.

Meanwhile, if the birds are flying around they aren't resting on the truck or touching it, so therefore their weight wouldn't be added to the truck.

The mass of the truck will remain the same as you cannot change the mass but the weight will vary depending on the items and objects placed in it.

4 0
3 years ago
An elevator and its load have a combined mass of 1650 kg. Find the tension in the supporting cable when the elevator, originally
gizmo_the_mogwai [7]

Answer:

Tension in the supporting cable is = 4,866 N ≅4.9 KN

Explanation:

First of all, we need to understand that tension is a force, so the motion law

F = Ma applies perfectly.

From Newtons third law of motion, action and reaction are equal and opposite. This means that the force experienced by the elevator, is equal to the tension experienced by the spring.

Parameters given:

Mass of load = 1650 kg

Acceleration of load = ?

The acceleration of the load can be obtained by diving the change in velocity by the time taken. But we need to know the time taken for the motion to 41 m.

Time taken = distance covered / velocity

= \frac{41m}{11m/s} = 3.73 seconds

∴Acceleration = ( initial velocity - final velocity )/ time taken

Note: Final velocity is = 0 since the body came to a rest.

Acceleration = \frac{11 - 0 m/s}{3.73s} = 2.95m/s^{2}

Force acting on the cable = mass of elevator × acceleration of elevator

= 1650 × 2.95 = 4869.5 kg ≅ 4.9 KN

6 0
3 years ago
7. A 1.0 kg metal head of a geology hammer strikes a solid rock with a velocity of 5.0 m/s. Assuming all the energy is retained
marta [7]

The increase in temperature of the metal hammer is 0.028 ⁰C.

The given parameters:

  • <em>mass of the metal hammer, m = 1.0 kg</em>
  • <em>speed of the hammer, v = 5.0 m/s</em>
  • <em>specific heat capacity of iron, 450 J/kg⁰C</em>

The increase in temperature of the metal hammer is calculated as follows;

Q = K.E\\\\mc \Delta T = \frac{1}{2}  mv^2\\\\\Delta T = \frac{v^2}{2 c}

where;

<em>c is the </em><em>specific heat capacity</em><em> of the metal hammer</em>

<em />

Assuming the metal hammer is iron, c = 450 J/kg⁰C

\Delta T = \frac{5^2}{2 \times 450} \\\\\Delta T = 0.028 \ ^0C

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.

Learn more about heat capacity here: brainly.com/question/16559442

8 0
3 years ago
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