Answer:
f1 = 58.3Hz, f2 = 175Hz, f3 = 291.6Hz
Explanation:
lets assume speed of sound is 350 m/s.
frequencies of a standing wave modes of an open-close tube of length L
fm = m(v/4L)
where m is 1,3,5,7......
and fm = mf1
where f1 = fundamental frequency
so therefore: f1 = 350 x 4 / 1.5
f1 = 58.3Hz
f2 = 3 x 58.3
f2 = 175Hz
f3 = 5 x 58.3
f3 = 291.6Hz
Answer:
6.75m/s
Explanation:
using the second equation of motion, the time is calculated.
and with the formula a= (v - u)/t
where a is acceleration but in this case it's deceleration (and should be negated as you solve it ) .
v is final velocity
u is initial velocity
t is time taken
Answer:
c
Explanation:
It light wave will travel at speed of light and go faster in its wavelength
Distance is 90km,time 1 hr
distance 2 is 82km,time 5 hrs
average speed=total distance travelled/total time taken.
90+82=172/5+1=6
average speed=28.7km over hour
