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2 years ago

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A positively charged particle initially at rest on the ground accelerated upward to 100m/s in 2.00s. If the particle has a charg

e-to-mass ratio of 0.100 C/kg and the electric field in this region is constant and uniform, what are the magnitude and direction of the electric field?

1 answer:

VashaNatasha [74]2 years ago

4 0

Answer:

Explanation:

From the question we are told that

The initial velocity is $u = 100 m/s$

The time taken is $t = 2.0 s$

The charge to mass ratio is $Q/m = 0.100 C/kg$

Generally the acceleration is mathematically evaluated as

$a = \frac{u}{t }$

substituting values

$a = \frac{100}{2}$

$a = 50 \ m/s^2$

The electric field is mathematical represented as

$E = \frac{(a+g)}{Q/m}$

substituting values

$E = \frac{(50+9.8)}{0.100}$

$E = 598 \ N/C$

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An object with a mass of 78kg is lifted through a height of 6 meters. How much work is done?

g100num [7]

Work = force x distance.

force = mass x acceleration

work = mass x acceleration x diastance

use acceleration of gravity in this problem

W (J) = m (kg) x a (m/s/s) x d (m)
W = 78 x 9.8 x 6
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2 years ago

An ordinary egg can be approximated as a 5.5-cm diameter sphere. The egg is initially at a uniform temperature of 8°C and is dro

kupik [55]

Answer:

a) $Q_{in} = 13.742\,kW$ , b) $\Delta S = 370.15\,\frac{kJ}{K}$

Explanation:

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b) The amount of entropy generation is determined by the Second Law of Thermodynamics:

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3 years ago

tatuchka [14]

1) 9.57 N

We have two forces applied on the apple:

- The force of gravity, in the downward direction:

W = 9.42 N

- The force exerted by the wind, in the horizontal direction (to the right):

Fw = 1.68 N

The two forces are perpendicular to each other, so we can find the magnitude of the net force by using Pythagorean's theorem.

Therefore, we have:

$F=\sqrt{W^2+F_w^2}=\sqrt{(9.42)^2+(1.68)^2}=9.57 N$

2) $10^{\circ}$

The direction of the net external force, measured from the downward vertical, can be measured using the following formula:

$\theta = tan^{-1}(\frac{F_x}{F_y})$

where

$F_x$ is the force in the horizontal direction

$F_y$ is the force in the vertical direction

In this problem,

$F_x = F_w = 1.68 N$

$F_y = W = 9.42 N$

and so we find:

$\theta = tan^{-1}(\frac{1.68}{9.42})=10^{\circ}$

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2 years ago

Elena-2011 [213]

Answer:

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3 years ago

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Answer:

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