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lesya692 [45]
3 years ago
10

Wolf spiders carry their young on their backs. How does this help in their survival?

Physics
2 answers:
Ivan3 years ago
6 0
It intimidates other spider because it makes them look bigger than they really are.
Rom4ik [11]3 years ago
3 0

Answer: It provides care to the young.

Wolf spiders are unique members of the spider species. They are unique in the sense they carry their young ones on the back after hatching of the eggs. The egg sac of these spiders remains attached at the spinnerets which are present in the end of the abdomen. After hatch the spiderlings climb up the back and remain their for several weeks until they develop large enough to disperse themselves.  

Therefore, It provides care to the young. is the correct option which reflects the fact that wolf spiders help their young ones for survival.

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3 years ago
How does radiation transfer thermal energy from the Sun to Earth?
Svetradugi [14.3K]

Answer:

The thermal energy is carried by electromagnetic waves

Explanation:

There are three types of transfer of heat (thermal energy):

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Indeed, the Sun emits a lot of electromagnetic radiation, which travels through space and eventually reaches the Earth, heating it.

4 0
3 years ago
Read 2 more answers
A sprinter accelerates at 7.5 m/s from rest in 2.0 s, what distance did she go? (15 m)
a_sh-v [17]

Answer:

<em>The sprinter traveled a distance of 7.5 m</em>

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the rate of change of the velocity of an object is constant.

The equation that rules the change of velocities is:

v_f=v_o+at\qquad\qquad [1]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The distance traveled by the object is given by:

\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]

Using the equation [1] we can solve for a:

\displaystyle a=\frac{v_f-v_o}{t}

The sprinter travels from rest (vo=0) to vf=7.5 m/s in t=2 s. Computing the acceleration:

\displaystyle a=\frac{7.5-0}{2}

a=3.75\ m/s^2

Now calculate the distance:

\displaystyle x=0*2+\frac{3.75*2^2}{2}

\displaystyle x=7.5\ m

The sprinter traveled a distance of 7.5 m

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Next, you can use the rate the Jetson's car is going (180km/h) and divide the 38,955.75 by it to see how many hours it would take at that constant speed.

38,955.75 / 180 = 216.42 hours

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Answer:

The two main reasons that your results might not match up each time are uncontrolled conditions and experimental error.

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