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kompoz [17]
3 years ago
11

Steam enters an adiabatic turbine at 400◦C, 2 MPa pressure. The turbine has an isentropic efficiency of 0.9. The exit pressure i

s set so that the actual work output from the turbine is 700 kJ/kg. Determine the required exit pressure and the actual exit temperature and quality, if saturated.

Engineering
1 answer:
pychu [463]3 years ago
8 0

Answer:

Explanation:

Find attached the solution

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Hx115 it's pretty fine looking

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3 years ago
Tech A says that thrust angle refers to the direction the front wheels are pointing. Tech B says that scrub radius refers to the
kenny6666 [7]

Both of the technicians are correct.

<u>Explanation:</u>

The thrust angle is defined as the angle formed by the imaginary line drawn perpendicular to the rear axis center line. It is used in alignment of the four wheels.

It is also used to determine the direction the front wheels are pointing. While the scrub radius is the intersecting point of the vertical center line of front tires with the imaginary line drawn from the steering knuckles.

Thus both the technicians are saying correct. The thrust angle and scrub radius are used to determine the alignment of wheels, if there is any misalignment in wheels then it needs to make it correct to prevent accidents.

4 0
3 years ago
2. A F-22 Raptor has just climbed through an altitude of 9,874 m at 1,567 kph when a disk
BabaBlast [244]

The pressure difference across the sensor housing will be "95 kPa".

According to the question, the values are:

Altitude,

  • 9874

Speed,

  • 1567 kph

Pressure,

  • 122 kPa

The temperature will be:

→ T = 15.04-[0.00649(9874)]

→     = 15.04-64.082

→     = -49.042^{\circ} C

now,

→ P_o = 101.29[\frac{(-49.042+273.1)}{288.08} ]^{(5.256)}

→      = 27.074

hence,

→ The pressure differential will be:

= 122-27

= 95 \ kPa

Thus the above solution is correct.

Learn more about pressure difference here:

brainly.com/question/15732832

3 0
3 years ago
The mathematical model for finite element method in structural mechanics is the
zysi [14]

Explanation:

Conservation of velocity equation

3 0
3 years ago
Read 2 more answers
A ductile hot-rolled steel bar has a minimum yield strength in tension and compression of 350 MPa. Using the distortion-energy a
Ratling [72]

Answer:

Explanation:

From  the given question:

Using the distortion energy theory to determine the  factors of safety  FOS can be expressed  by the relation:

\dfrac{Syt}{FOS}= \sqrt{ \sigma x^2+\sigma  y^2-\sigma x \sigma y+3 \tau_{xy^2}}

where; syt = strength in tension and compression = 350 MPa

The maximum shear stress theory  can be expressed as:

\tau_{max} = \dfrac{Syt}{2FOS}

where;

\tau_{max} =\sqrt{ (\dfrac{\sigma x-\sigma  y}{2})^2+ \tau _{xy^2

a. Using distortion - energy theory formula:

\dfrac{350}{FOS}= \sqrt{94^2+0^2-94*0+3 (-75)^2}}

\dfrac{350}{FOS}=160.35

{FOS}=\dfrac{350}{160.35}

FOS = 2.183

USing the maximum-shear stress theory;

\dfrac{350}{2 FOS}  =\sqrt{ (\dfrac{94-0}{2})^2+ (-75)^2

\dfrac{350}{2 FOS}  =88.51

\dfrac{350}{ FOS}  =2 \times 88.51

{ FOS}  =\dfrac{350}{2 \times 88.51}

FOS = 1.977

b. σx = 110 MPa, σy = 100 MPa

Using distortion - energy theory formula:

\dfrac{350}{FOS}= \sqrt{ 110^2+100^2-110*100+3(0)^2}

\dfrac{350}{FOS}= \sqrt{ 12100+10000-11000

\dfrac{350}{FOS}=105.3565

FOS=\dfrac{350}{105.3565}

FOS =3.322

USing the maximum-shear stress theory;

\dfrac{350}{2 FOS}  =\sqrt{ (\dfrac{110-100}{2})^2+ (0)^2

\dfrac{350}{2 FOS}  ={ (\dfrac{110-100}{2})^2

\dfrac{350}{2 FOS}  =25

FOS = 350/2×25

FOS = 350/50

FOS = 70

c. σx = 90 MPa, σy = 20 MPa, τxy =−20 MPa

Using distortion- energy theory formula:

\dfrac{350}{FOS}= \sqrt{ 90^2+20^2-90*20+3(-20)^2}

\dfrac{350}{FOS}= \sqrt{ 8100+400-1800+1200}

\dfrac{350}{FOS}= 88.88

FOS = 350/88.88

FOS = 3.939

USing the maximum-shear stress theory;

\dfrac{350}{2 FOS}  =\sqrt{ (\dfrac{90-20}{2})^2+ (-20)^2

\dfrac{350}{2 FOS}  =\sqrt{ (35)^2+ (-20)^2

\dfrac{350}{2 FOS}  =\sqrt{ 1225+ 400

\dfrac{350}{2 FOS}  =40.31

FOS}  =\dfrac{350}{2*40.31}

FOS = 4.341

7 0
3 years ago
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